Find angles b,c and d

Mathematics

1 answer:

Mazyrski [523]3 years ago

8 0

Answer:

B = 73°, c = 107°, d= 107°

Step-by-step explanation:

$b + 107 \degree = 180 \degree..(straight \: line \: \angle s) \\ b = 180 \degree - 107 \degree \\ \huge \red{ \boxed{b = 73 \degree}} \\ \\ \huge \purple{ \boxed{c = 107 \degree }}\\..(vertical \: \angle s) \\ \\ \huge \orange{ \boxed{d = 107 \degree }}\\..(corresponding \: \angle s) \\ \\$

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rectangle will have length 3n+ 6 and height 2n−1 inches, while the square will have side length n+ 2inches. Find the perimeter a

kifflom [539]

Answer:

Perimeter: 2(3x+6)+ 2(2x-4)

X=9

Step-by-step explanation:

In order to create the expression you just have to remember that the perimeter of a rectangle equals 2 bases plus 2 sides, so the expression would be:

Perimeter: 2(heights)+ 2(bases)

Perimeter: 2(3x+6)+ 2(2x-4)

IN order to solve for X we just have to insert the value of perimeter, which is 94:

Perimeter: 2(3x+6)+ 2(2x-4)

94=2(3x+6)+ 2(2x-4)

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3 years ago

An athletic field is a 48 yd-by-96 yd rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surr

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The distance would be equal to 2 times the longest side of the rectangle plus twice the shortest side multiplied by pi / 2 for the semicircle, that is:

longest side 96 and shortest 48

D = 2 * (96) + 2 * (1/2) * pi * 48

D = 192 + pi * 48

This shorter side, which starts at 48, will expand each time by two more in proportion to 20 of the running track between 8 than the number of divisions, that is, 2 * (20/8) = 5

In other words, there are 8 distances, like this:

D1 = 192 + 3.14 * 48 = 342.72 yd

D2 = 192 + 3.14 * (48 + 5) = 358.42 yd

D3 = 192 + 3.14 * (48 + 10) = 374.12 yd

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D8 = 192 + 3.14 * (48 + 35) = 452.62 yd

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3 years ago

60 - 3d + 20 - 6 = 4d