Given:
QSR is a right triangle.
QT = 10
TR = 4
To find:
The value of q.
Solution:
Hypotenuse of QSR = QT + TR
= 10 + 4
= 14
Geometric mean of similar right triangle formula:


Do cross multiplication.


Switch the sides.

Taking square root on both sides.

The value of q is
.
Answer:
1/4
Step-by-step explanation:
Answer:
The correct answer is there are 3 cages and 4 tigers.
Step-by-step explanation:
Let there be x cages and y tigers.
According to the first condition, if we put one tiger in each cage, one tiger is left over.
∴ y - x =1
According to the second condition, if we put two tigers in each cage, one cage is left over.
∴ x -
=1
⇒ 2x - y = 2
Therefore adding both the equations we get,
y - x + 2x - y = 2 + 1
⇒ x = 3
⇒ y = 4
Therefore there are 4 tigers and 3 cages.
Answer:
Probabilty of first component drawn defective= 0.1161
Probability of second component drawn defective= 0.1560
Step-by-step explanation:
Total component = 9
Defective component= 3
Non-defective component= 6
Probability of defective= 3/9
= 0.3333
Probabilty of non defective= 1-0.3333
= 0.6666
Probabilty of first component drawn is defective
= 9C1(0.333)¹(0.6666)^8
= 9(0.3333)(0.0387)
= 0.1161
Probabilty of second component is defective
= 8C1(0.3333)¹(0.6666)^7
= 8(0.3333)(0.0585)
= 0.1560
Answer:
(3x-4)(2x+5)
Step-by-step explanation:
6x^2 + 7x + 24
= 6x^2 + (15-8)x + 24
= 6x^2 + 15x - 8x + 24
= 3x( 2x+5 ) - 4( 2x+5 )
= (3x-4)(2x+5)