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balandron [24]
3 years ago
10

Find the area of this triangle

Mathematics
1 answer:
uysha [10]3 years ago
3 0

Answer:

i think the answer is 67.5

You might be interested in
Why is the value of q?
Rudiy27

Given:

QSR is a right triangle.

QT = 10

TR = 4

To find:

The value of q.

Solution:

Hypotenuse of QSR = QT + TR

                                 = 10 + 4

                                 = 14

Geometric mean of similar right triangle formula:

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{14}{q} =\frac{q}{4}

Do cross multiplication.

$\Rightarrow14\times 4 =q\times q

$\Rightarrow 56 =q^2

Switch the sides.

$\Rightarrow q^2 =56

Taking square root on both sides.

\Rightarrow q =2 \sqrt{14}

The value of q is 2 \sqrt{14}.

8 0
3 years ago
Express 0.75 as a fraction in its lowest terms
Scilla [17]

Answer:

1/4

Step-by-step explanation:

7 0
4 years ago
You have some tigers. You have some cages. If you put one tiger in each cage, your will have one tiger left over. If you put two
vredina [299]

Answer:

The correct answer is there are 3 cages and 4 tigers.

Step-by-step explanation:

Let there be x cages and y tigers.

According to the first condition, if we put one tiger in each cage, one tiger is left over.

∴ y - x =1

According to the second condition, if we put two tigers in each cage, one cage is left over.

∴ x - \frac{y}{2} =1

⇒ 2x - y = 2

Therefore adding both the equations we get,

y - x + 2x - y = 2 + 1

⇒ x = 3

⇒ y = 4

Therefore there are 4 tigers and 3 cages.

6 0
4 years ago
A lot of 9 components contains 3 that are defective. Two components are drawn at random and tested. Let be the event that the fi
kirza4 [7]

Answer:

Probabilty of first component drawn defective= 0.1161

Probability of second component drawn defective= 0.1560

Step-by-step explanation:

Total component = 9

Defective component= 3

Non-defective component= 6

Probability of defective= 3/9

= 0.3333

Probabilty of non defective= 1-0.3333

= 0.6666

Probabilty of first component drawn is defective

= 9C1(0.333)¹(0.6666)^8

= 9(0.3333)(0.0387)

= 0.1161

Probabilty of second component is defective

= 8C1(0.3333)¹(0.6666)^7

= 8(0.3333)(0.0585)

= 0.1560

7 0
3 years ago
If someone could help me I would really appreciate it!<br><br> Factor by slide and divide!
OleMash [197]

Answer:

(3x-4)(2x+5)

Step-by-step explanation:

6x^2 + 7x + 24

= 6x^2 + (15-8)x + 24

= 6x^2 + 15x - 8x + 24

= 3x( 2x+5 ) - 4( 2x+5 )

= (3x-4)(2x+5)

5 0
3 years ago
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