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AURORKA [14]
3 years ago
15

Put 0.7 as a fraction in simplest form

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0
0.7 is just 7 tenths which is literally 7/10.
You might be interested in
URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!
Blababa [14]

For this case we have that by definition, the circumference of a circle is given by:

C = \pi * d

Where:

d: It is the diameter of the circle

They tell us that:

d = \frac {35} {2}\\\pi = \frac {22} {7}

Substituting:

C = \frac {22} {7} * \frac {35} {2}\\C = \frac {770} {14}\\C = 55 \ cm

Thus, the circumference of the circle is 55 centimeters.

Answer:

Option B

6 0
2 years ago
Read 2 more answers
If 5% of the total ticket is $125 what is the value of the total ticket sales
andriy [413]
If you would like to know what is the value of the total ticket sales, you can calculate this using the following steps:

$x ... the value of the total ticket sales

5% of $x is $125
5/100 * x = 125     /*100/5
x = 125 * 100 / 5
x = $2500

Result: The value of the total ticket sales is $2500.
6 0
2 years ago
Read 2 more answers
8. Hassan made a vegetable salad with 2 3/8 pounds
amm1812

let's convert firstly the mixed fractions to improper fractions and then add up.

\bf \stackrel{mixed}{2\frac{3}{8}}\implies \cfrac{2\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{19}{8}}~\hfill \stackrel{mixed}{1\frac{1}{4}}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}} \\\\\\ \stackrel{mixed}{2\frac{7}{8}}\implies \cfrac{2\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{23}{8}} \\\\[-0.35em] ~\dotfill

\bf \cfrac{19}{8}+\cfrac{5}{4}+\cfrac{23}{8}\implies \stackrel{\textit{using an LCD of 8}}{\implies \cfrac{(1)19+(2)5+(1)23}{8}}\implies \cfrac{19+10+23}{8} \\\\\\ \cfrac{52}{8}\implies \cfrac{13}{2}\implies 6\frac{1}{2}

5 0
3 years ago
1. Cabrini goes out for dinner, and the price of her meal is $18. The sales tax on the meal is 6%, and she also wants to leave a
Daniel [21]

Answer:

19.64

Step-by-step explanation:

7 0
3 years ago
Determine whether ∆DEF=∆JKL, given that D(2,0), E(5,0), F(5,5), J(3,-7), K(6,-7), and L(6,-2)
raketka [301]

Answer:

Yes , triangle DEF is congruent to JKL

Step-by-step explanation:

Given:

The coordinates of triangle DEF are;

D (2, 0)

E(5. 0)

F(5, 5)

and

the coordinates of triangle JKL are:

J(3, -7)

K(6, -7)

L (6, -2)

The rule of translation is used on triangle DEF to get triangle JKL:

(x , y) \rightarrow (x+1 , y-7)

i.e

D (2, 0) \rightarrow (2+1 , 0-7) = (3, -7) =  J

E (5, 0) \rightarrow (5+1 , 0-7) = (6, -7) =  K

F (5, 5) \rightarrow (5+1 , 5-7) = (6, -2) = L

As, we know that two triangles are known as congruent if there is an isometry mapping one of the triangles to the other.

therefore, triangle DEF congruent  to triangle JKL



8 0
3 years ago
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