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Lostsunrise [7]
2 years ago
11

In general, the median of a data set is less resistant to outliers than the mean. A. True B. False

Mathematics
2 answers:
Leto [7]2 years ago
7 0
A. true, the median of a data set is less resistant to outliers than the mean
antiseptic1488 [7]2 years ago
3 0

Answer:

FALSE  is the correct answer

Step-by-step explanation:

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What is the value of the expression?<br> 8 1/2-2+4 3/4
kodGreya [7K]
11 1/4 or 11.25 is the answer
7 0
3 years ago
Application of Geometric Series
Gnoma [55]

Answer:

  7.2224

Step-by-step explanation:

The value of the summation is given by the formula ...

  Sn = (a1)(1 -r^n)/(1 -r) . . . . . where a1 is the first of n terms, and r is the common ratio.

Your sum has first term and ratio ...

  a1 = 2(0.6) . . . . . summation term for n=1

  r = 0.6

So the sum is ...

  \displaystyle \sum_{n=1}^4{2(0.6^n)}=2(0.6)\dfrac{1-0.6^4}{1-0.6}=\dfrac{1.2}{0.4}(0.8704) = 2.6112

Then the value of the entire given expression is ...

  \displaystyle 2+2\sum_{n=1}^4{}2(0.6^n)=2+2(2.6112)=\boxed{7.2224}

_____

A calculator can help you find the value.

6 0
2 years ago
Please help, will mark you as the brainiest! Please do NOT answer if you don’t know it!
Sholpan [36]

Answer:

if oq or and os are bisectors then MN is 40, also it is a perpendicular angle so it would also be 40

Step-by-step explanation:

3 0
2 years ago
What is the base plan for the set of stacked cubes? Why?
docker41 [41]
Base should look like __ from above.
_ _
|_||_|
|_| _
|_||_|
If you were to look at the bottom of the stacked cubes from the bottom it should look like __.
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_ |_|
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7 0
3 years ago
The barbers profit p each week depends on his charge c per haircut. It is modeled by the equation p= -200c^2+2400c-4700. What pr
shepuryov [24]

Answer:

0 ≤ c ≤ 12

Step-by-step explanation:

The function can be rearranged to ...

p = 200c(12 -c) -4700

suggesting that revenue will be zero for a charge of 0 or for a charge of 12, and that fixed expenses are 4700. Charges less than 0 are uninteresting, and charges high enough to cause the number of customers to be negative also don't make any sense in this context.

Though out of the range of likely consideration, charges low or high enough to cause profit to be negative (more than 9.54, for example) seemingly can be reasonably modeled by this function.

5 0
2 years ago
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