Answer:
Step-by-step explanation:
In each case we find the discriminant b^2 - 4ac.
If the discriminant is negative, we have two unequal, complex roots.
If the discriminant is zero. we have two equal, real roots.
If the discriminant is positive, we have two unequal real roots.
#51: 8v^2 - 12v + 9: the discriminant is (-12)^2 - 4(8)(9) = -144. we have two unequal, complex roots
#52: (-11)^2 - 4(4)(-14) = 121 + 224 = 345. we have two unequal real roots.
#53: (-5)^2 - 4(7)(6) = 25 - 168 (negative). we have two unequal, complex roots.
#54: (4)^2 - 16 = 0. We have two equal, real roots.
For this case we must find the product of the following expression:
![\sqrt [3] {5} * \sqrt {2}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B5%7D%20%2A%20%5Csqrt%20%7B2%7D)
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20m%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bm%7D%20%7Bn%7D%7D)
We rewrite the expression using the lowest common index of 6, then:
We rewrite the terms in an equivalent way:
We rewrite the expression using the property mentioned:
![\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =](https://tex.z-dn.net/?f=%5Csqrt%20%5B6%5D%20%7B5%20%5E%202%7D%20%2A%20%5Csqrt%20%5B6%5D%20%7B2%20%5E%203%7D%20%3D)
We combine using the product rule for radicals:
![\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%7D%20%2A%20%5Csqrt%20%5Bn%5D%20%7Bb%7D%20%3D%20%5Csqrt%20%5Bn%5D%20%7Bab%7D)
So:
![\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}](https://tex.z-dn.net/?f=%5Csqrt%20%5B6%5D%20%7B5%20%5E%202%20%2A%202%20%5E%203%7D%20%3D%5C%5C%5Csqrt%20%5B6%5D%20%7B25%20%2A%208%7D%20%3D%5C%5C%5Csqrt%5B6%5D%7B200%7D)
ANswer:
Option b
Answer:
https://www.ringgold.org/cms/lib/PA01916235/Centricity/Domain/227/Algebra%20I%20Keystone%20Review%20Packet%20Answer%20Key.pdf
there you go just a copy and a paste
