For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Answer:
I was expecting a mirror but okay
Answer:
Step-by-step explanation:
on the edge of a cliff overlooking the Pacific ocean. You see a sailboat down in the water below you. The angle of depression to the sailboat is 28◦ . A quick tells you that the cliff you’re standing on is 150ft. How far away from the boat are you, in feet, rounded to one decimal place?(30pts)
We solve using the Trigonometric function of TANGENT
tan 28 = 150/x
Answer: 39
Step-by-step explanation: x=13. so 5-2=3 x 13 = 39
espero que esto ayude :)
hmmm let's find the distance between B and C first off.

hmmm if BC is that much, then AB + AC = 7, since AB + AC + BC = 12 which is the perimeter, Check the picture below.