Solve the equation by the square root (7x+4)^2=4

Mathematics

1 answer:

hjlf3 years ago

4 0

Step-by-step explanation:

(7x+4)^2 = 4

7x^2 + 4^2 = 4

49x + 16 = 4

-16 -16

49x = -12

--- ----

49 49

x= 4.0

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$Steps:$

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$\frac{-4r}{4},\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b},\\-\frac{4r}{4},\\\mathrm{Divide\:the\:numbers:}\:\frac{4}{4}=1,\\-r,\\-r+\frac{5r}{3}$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:r=\frac{r3}{3},\\\frac{5r}{3}-\frac{r\cdot \:3}{3}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c},\\\frac{5r-r\cdot \:3}{3}$