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NARA [144]
3 years ago
13

Professional plumbers suggest that a sewer pipe should be sloped 0.25 inch for every foot. find the recommended slope for a sewe

r pipe
Mathematics
1 answer:
erik [133]3 years ago
5 0

We have been given that professional plumbers suggest that a sewer pipe should be sloped 0.25 inch for every foot.

Therefore, we can find the slope as:

\text{Slope}=\frac{0.25\text{ inch}}{\text{1 foot}}=\frac{0.25\text{ inch}}{\text{12 inch}}

\text{Slope}=\frac{0.25}{12}=\frac{25}{1200}=\frac{1}{48}

Therefore, the recommended slope for a sewer pipe is \frac{1}{48}


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Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro
Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is 25(4+\sqrt{2})\ units   or approximately  135.4\ units

Part 3) The area is 937.5\ units^2

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

P=AB+BC+CD+AD

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}

d=\sqrt{(-24)^{2}+(7)^{2}}

d=\sqrt{625}

d_A_B=25\ units

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

d=\sqrt{(-8+22)^{2}+(27+21)^{2}}

d=\sqrt{(14)^{2}+(48)^{2}}

d=\sqrt{2,500}

d_B_C=50\ units

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

d=\sqrt{(9+8)^{2}+(-4-27)^{2}}

d=\sqrt{(17)^{2}+(-31)^{2}}

d=\sqrt{1,250}

d_C_D=25\sqrt{2}\ units

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

d=\sqrt{(9-2)^{2}+(-4+28)^{2}}

d=\sqrt{(7)^{2}+(24)^{2}}

d=\sqrt{625}

d_A_D=25\ units

Find the perimeter

P=25+50+25\sqrt{2}+25

P=(100+25\sqrt{2})\ units

simplify

P=25(4+\sqrt{2})\ units ----> exact value

P=135.4\ units

therefore

The perimeter is 25(4+\sqrt{2})\ units   or approximately  135.4\ units

step 3

Find the area

The area of trapezoid is equal to

A=\frac{1}{2}[BC+AD]AB

substitute the given values

A=\frac{1}{2}[50+25]25=937.5\ units^2

4 0
3 years ago
the area of a gymnasium floor is 264 square yard. the floor is 11 yards wide . how long is the floor?
Alekssandra [29.7K]
Area = Length x Width (A = L x W)

A = 264, W = 11, L = ?

Rewrite the equation to find L. In order to reverse multiplication, you must divide.

L = A / W

L = 264 / 11 = 24 yards
4 0
2 years ago
Read 2 more answers
TRUE OR FALSE: point (1, -1) and (-1, 1) lies in the same quadrant.
earnstyle [38]

Answer:

False.

Step-by-step explanation:

Point (1, -1) is located in Quadrant 4, while point (-1, 1) is in Quadrant 2.

I hope this helps...have a great day! ❤

6 0
3 years ago
Read 2 more answers
A color printer prints 31 pages in 9 minutes. How many pages does it print per minute?
djyliett [7]
According to my calculations, it would take approximately 3.4 (being in decimal form) pages PER minute or Just 3 minuets being rounded to the nearest tenth. If I am I correct please correct me. I used a calculator.
7 0
2 years ago
Use set of notation to write the domain and range of the function y=-3x(x+1)^2+3 shown in graph
anygoal [31]

The domain of a function is the set of values of x in which the function can be calculated.

The range of a function is the associated values of the function respect to the domain.

You have the following function:

y=-3(x+1)^2+3

In order to determine the domain and range of the previous function, you consider that the given function is available for any value of x. Then, you have:

dom y: -∞ ≤ x ≤ ∞ : (-∞,∞)

The range of the function can be determine by noticing, on the graph, that the maximum value of the function is y=3 and also you can notice that there is no a limit for negatives values of the function. Then, you have:

ran y: -∞ ≤ y ≤ 3 : (-∞,3]

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