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Marina86 [1]
3 years ago
14

Part A: Solve for A

Mathematics
1 answer:
Naddik [55]3 years ago
6 0

Answer:

a=25

angle abq=139 degrees

bcr=41

Step-by-step explanation:

(2a-9)+(5a+14)=180

7a+5=180

7a=175

a=25

2(25)-9=41

180-41=139

angle abq=139 degrees

bcr=41

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Select the expression that has a sum of seventy-four hundredths.
Alex_Xolod [135]
It should be D

Explanation:
“Four-tenths (0.4) plus thirty-four hundredths (0.34).”

0.4
0.34
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0.74

Hope this helps! :D
4 0
2 years ago
Ecuación:
KIM [24]
Queremos tener todos los variables del mismo typo en un lado así que vamos a mover la -x a la izquierda, y el 15 a la derecha.
15 + 3x = 21 - x
+x +x
————————
15 + 4x = 21
-15 -15
———————
4x = 6
— —
4 4
X = 1.5 para ver si es correcto puedes tratar de poner 1.5 en lugar de la x y te saldrá una ecuación correcta :), déjame saber si tienes preguntas espero que eso hizo sentido.
6 0
3 years ago
Graph 3x+y=-10 -x+3y=0
nikdorinn [45]

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

We have the equations in the standard form. Convert to the slope-intercept form:

3x+y=-10            <em>subtract 3x from both sides</em>

y=-3x-10

-x+3y=0             <em>add x to both sides</em>

3y=x             <em>divide both sides by 3</em>

y=\dfrac{1}{3}x

-----------------------------------------------------

We need only two points to plot a graph of each function.

y=-3x-10

for x = 0 and for x = -3:

y=-3(0)-10=0-10=-10\to(0,\ -10)\\\\y=-3(-3)-10=9-10=-1\to(-3,\ -1)

y=\dfrac{1}{3}x

for x = 0 and for x = -3:

y=\dfrac{1}{3}(0)=0\to(0,\ 0)\\\\y=\dfrac{1}{3}(-3)=-1\to(-3,\ -1)

Look at the picture.

3 0
3 years ago
Which of the following graphs shows a system with a infinite number of solutions
fiasKO [112]

Answer:

D

Step-by-step explanation:

There is only one line that crosses the origin. Because there is only one line, there is an infinite amount of solutions.

8 0
3 years ago
What's 1+0? Or One plus zero? Plzzzz helpp
melisa1 [442]

Answer:

1

Step-by-step explanation:

8 0
3 years ago
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