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Igoryamba
3 years ago
8

Please answer this correctly

Mathematics
1 answer:
meriva3 years ago
4 0

Answer:

33.3%

Step-by-step explanation:

The numbers greater than 6 from the spinner are 7 and 8.

2 numbers out of total 6 numbers.

2/6 = 1/3

= 0.333

= 33.3%

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-6+(-1)=<br> ..................
Mice21 [21]

Answer:

It's -7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose you want to fence in some land along the edge of a straight river. the fenced area will be in the shape of a rectangle,
m_a_m_a [10]
For the largest area, half the fence is used parallel to the river, and the other half is used for the two ends of the rectangular space.

The dimensions are 475 m by 237.5 m.

_____
Let x represent the length along the river. Then the area (A) is found as
.. A = x*(950 -x)/2
This equation describes a parabola with its vertex (maximum) halfway between the zeros of x=0 and x=950. That is, the maximum area is achieved when half the fence is used parallel to the river.

7 0
3 years ago
Which is greatest 3/5, 0.70, or 65%? Tell how you know.
Leni [432]
3/5 = .60, 65% = .65, 0.70 is the greatest
8 0
3 years ago
a math teacher claims that she has developed a review course that increases the score of students on the math portion of a colle
madam [21]

Answer:

A.

H_0: \mu\leq514\\\\H_1: \mu>514

B. Z=2.255. P=0.01207.

C. Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. P(z>0.94)=0.1736

Step-by-step explanation:

<em>A. state the null and alternative hypotheses.</em>

The null hypothesis states that the review course has no effect, so the scores are still the same. The alternative hypothesis states that the review course increase the score.

H_0: \mu\leq514\\\\H_1: \mu>514

B. test the hypothesis at the a=.10 level of confidence. is a mean math score of 520 significantly higher than 514? find the test statistic, find P-value. is the sample statistic significantly higher?

The test statistic Z can be calculated as

Z=\frac{M-\mu}{s/\sqrt{N}} =\frac{520-514}{119/\sqrt{2000}}=\frac{6}{2.661}=2.255

The P-value of z=2.255 is P=0.01207.

The P-value is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.

Then we can conclude that the score of 520 is significantly higher than 514, in this case, specially because the big sample size.

C.​ do you think that a mean math score of 520 vs 514 will affect the decision of a school admissions adminstrator? in other words does the increase in the score have any practical significance?

Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. test the hypothesis at the a=.10 level of confidence with n=350 students. assume that the sample mean is still 520 and the sample standard deviation is still 119. is a sample mean of 520 significantly more than 514? find test statistic, find p value, is the sample mean statisically significantly higher? what do you conclude about the impact of large samples on the p-value?

In this case, the z-value is

Z=\frac{520-514}{s/\sqrt{n}} =\frac{6}{119/\sqrt{350}} =\frac{6}{6.36} =0.94\\\\P(z>0.94)=0.1736>\alpha

In this case, the P-value is greater than the significance level, so there is no evidence that the review course is increasing the scores.

The sample size gives robustness to the results of the sample. A large sample is more representative of the population than a smaller sample. A little difference, as 520 from 514, but in a big sample leads to a more strong evidence of a change in the mean score.

Large samples give more extreme values of z, so P-values that are smaller and therefore tend to be smaller than the significance level.

8 0
2 years ago
Tom was driving 20.3 meters per second in a 45 mile per hour zone. Was Tom speeding? Explain using a unit conversion as well as
My name is Ann [436]

Answer:

Tom was speeding.

Step-by-step explanation:

The driving speed of Tom = 20.3 meters per second.

Speed allowed in the zone = 45 miles per hour zone.

Since the unit of speed allowed is given in miles per hour but the speed of tom is given in meters per second. So, first, we have to convert the meter per second into mile per hour then we can compare and find that Tom is speeding or not.  

1 mile = 1609.34 meters

1 hour = 3600 second

Now convert 20.3 into mile per hour.

20.3 meters per second. = (20.3 / 1609.34)*3600 = 45.40981 mile per hour.

Since Tom’s speed is more than the allowed speed so he is speeding.

7 0
2 years ago
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