Answer: No .
Step-by-step explanation:
There are special cases where a person can use right and left hand equally well . I.e ambidextrous .
In statistical terms and probability theory, two events (or propositions) are mutually exclusive or disjoint if they cannot both occur at the same time .however in this case it may occur that the person is right and left handed at the same time .
I do not know exactly, but it seems to be correct A = Pe^(r*t) Compounding continously
17,000 = Пэ^(.051*14)
17,000/e^(.714) = P
$8324.59 = P
Answer:
(a + b + 2c)(a² + 2ab + b² - 2ac - 2bc + 4c²)
Step-by-step explanation:
Given
(a + b)³ + 8c³ ← this is a sum of cubes and factors in general as
a³ + b³ = (a + b)(a² - ab + b²)
Thus
(a + b)³ + 8c³
= (a + b)³ + (2c)³
= (a + b + 2c)( (a + b)² - 2c(a + b) + (2c)² )
= (a + b + 2c)(a² + 2ab + b² - 2ac - 2bc + 4c²)
Answer:
<h2>(f · g)(x) is odd</h2><h2>(g · g)(x) is even</h2>
Step-by-step explanation:
If f(x) is even, then f(-x) = f(x).
If g(x) is odd, then g(-x) = -g(x).
(f · g)(x) = f(x) · g(x)
Check:
(f · g)(-x) = f(-x) · g(-x) = f(x) · [-g(x)] = -[f(x) · g(x)] = -(f · g)(x)
(f · g)(-x) = -(f · g)(x) - odd
(g · g)(x) = g(x) · g(x)
Check:
(g · g)(-x) = g(-x) · g(-x) = [-g(x)] · [-g(x)] = g(x) · g(x) = (g · g)(x)
(g · g)(-x) = (g · g)(x) - even
Answer:
4.24
Step-by-step explanation:
looked it up on google
google is never wrong
