36-(b^2+c^2-2bc)=36-(b-c)^2=6^2-(b-c)^2= (6+b-c)[6-(b-c)]=(6+b-c)(6-b+c)
Answer:
Step-by-step explanation:
So we know that the slope-intercept form of an equation is:

And we are given the equation: 
So we need to subtract 2x from both sides:

And then divide both sides by 3:

Answer:
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Step-by-step explanation:
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