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elena-14-01-66 [18.8K]
4 years ago
12

Which of the following describes one of the main features of wave-particle duality?

Physics
1 answer:
steposvetlana [31]4 years ago
8 0
<h2>Answer:  as mass increases, the wave nature of matter is less easy to observe.</h2>

At the beginning of the 20th century the French physicist Louis De Broglie proposed the existence of matter waves, that is to say that <u>all matter has a wave associated with it.</u>

In this sense, the de Broglie wavelength \lambda is given by the following formula:

\lambda=\frac{h}{p}   (1)

Where:

h is the Planck constant

p is the momentum of the atom, which is given by:

p=m.v (2)

Where:

m is the mass

v is the velocity

Substituting (2) in (1):

\lambda=\frac{h}{m.v}[\tex]   (3)As we can see, if we increase the mass, the wavelength decreases (because [tex]\lambda is inversely proportional to m).

Therefore, if the wavelength decreases the wave nature of matter is less easy to observe.

The other options are incorrect because:

a) as v increases \lambda decreases and the particle nature matter becomes more evident

b) as p decreases \lambda increases and the wave nature matter becomes more evident

c) There is also a relation between the wavelength and the energy E:

\lambda=\frac{hc}{E}

So, as energy increases, the particle nature matter becomes more evident and the wave nature of matter becomes harder to observe

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A harmonic wave on a string is described by
xxMikexx [17]

\huge{\bold{\orange{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

A harmonic wave on a string is described by

\sf{ Y( x, t)  = 0.1 sin(300t + 0.01x + π/3)}

  • x is in cm and t is in seconds

<h3><u>Answer </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

<u>Equation </u><u>for </u><u>travelling </u><u>wave </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = Asin(ωt + kx + Φ)...eq(1)}

<u>Equation</u><u> </u><u>for </u><u>stationary </u><u>wave </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = Acos(ωt - kx )...eq(2)}

<u>Given </u><u>equation </u><u>for </u><u>wave </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = 0.1 \:sin(300t + 0.01x + π/3)...eq(3)}

<u>On </u><u>comparing </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>,</u><u> </u><u>(</u><u>2</u><u>)</u><u> </u><u>and </u><u>(</u><u>3</u><u>)</u>

We can conclude that, Given wave represent travelling wave.

<h3><u>Answer </u><u>2</u><u> </u><u>:</u><u>-</u></h3>

From solution 1 , We can say that,

\sf{ Y( x, t)  = 0.1 \: sin(300t + 0.01x + π/3).}

It is travelling from right to left direction

Hence, The direction of its propagation is right to left that is towards +x direction.

<h3><u>Answer </u><u>3</u><u> </u><u>:</u><u>-</u></h3>

Here, We have to find the wave period

<u>We </u><u>know </u><u>that</u><u>, </u>

Wave period = wavelength / velocity

<u>Wave </u><u>equation</u><u> </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = 0.1 \:sin(300t + 0.01x + π/3).}

  • ω = 300rad/s
  • k = 0.01

<u>We </u><u>know </u><u>that</u><u>, </u>

\sf{v =}{\sf{\dfrac{ ω}{2π}}}{\sf{\: and\:}}{\sf{ λ =}}{\sf{\dfrac{ 2π}{k}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ wave\: period =}{\sf{\dfrac{ 2π/k}{ω/2π  }}}

\sf{ wave \:period = }{\sf{\dfrac{k}{ω}}}

\sf{ wave\: period =}{\sf{\dfrac{ 0.01}{300}}}

\sf{ wave\: period = 0.000033\: s}

<h3><u>Answer </u><u>4</u><u> </u><u>:</u><u>-</u></h3>

The wavelength of given wave

\bold{ λ = }{\bold{\dfrac{2π}{k}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ λ = }{\sf{\dfrac{2 × 3.14 }{0.01}}}

\sf{ λ = }{\sf{\dfrac{6.28}{0.01}}}

\sf{ λ = 628 \: cm }

<h3><u>Answer </u><u>5</u><u> </u><u>:</u><u>-</u></h3>

We have wave equation

\sf{ Y( x, t)  = 0.1 sin(300t + 0.01x + π/3).}

<u>Travelling </u><u>wave </u><u>equation </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = A\:sin(ωt + kx + Φ)...eq(1)}

<u>Therefore</u><u>, </u>

Amplitude of the wave particle

\sf{ A = 0.1 \: cm}

Hence, The amplitude of the particle is 0.1 cm

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A women steps in front of a child to keep them from running. what best terms describe the example
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If this is an English Question list the terms so we can pick from those. Otherwise we dont have the correct terms to answer the question
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Newton’s law of cooling states that dx dt = −k(x−A) where x is the temperature,t is time, A is the ambient temperature, and k &g
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Answer:

a)X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}

b)Does not affect the long term.

Explanation:

Given that

\dfrac{dx}{dt}=-k(x-A)

A = A0 cos(ωt)

\dfrac{dx}{dt}=-k(x-A_o cos(\omega t))

\dfrac{dx}{dt}+kx=kA_o cos(\omega t)

This is linear equation so integration factor ,I

I=e^{\int kdt}

I=e^{kt}

Now by using linear equation property

e^{kt} X=\int e^{kt} kA_o cos(\omega t) dt +C

e^{kt} X= kA_o \dfrac{e^{kt}}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+C

X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}

b)

at t= 0

X(0)=\dfrac{k^2A_o}{\omega^2+k^2}+C

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So the initial condition does not affect the long term.

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What term is used to describe a system that looses energy to objects that are not part of the system
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Answer: Open system

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The reaction force is the glove pushing against the ball because the reaction force would be the ball pushing onto the glove.

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