Answer:
121.3 cm^3
Explanation:
P1 = Po + 70 m water pressure (at a depth)
P2 = Po (at the surface)
T1 = 4°C = 273 + 4 = 277 K
V1 = 14 cm^3
T2 = 23 °C = 273 + 23 = 300 K
Let the volume of bubble at the surface of the lake is V2.
Density of water, d = 1000 kg/m^3
Po = atmospheric pressure = 10^5 N/m^2
P1 = 10^5 + 70 x 1000 x 10 = 8 x 10^5 N/m^2
Use the ideal gas equation
By substituting the values, we get
V2 = 121.3 cm^3
Thus, the volume of bubble at the surface of lake is 121.3 cm^3.
A is the answer you can believe me
1.
Answer:
Part a)
Part b)
Explanation:
Part a)
Length of the rod is 1.60 m
diameter = 0.550 cm
now if the current in the ammeter is given as
V = 17.0 volts
now we will have
R = 0.91 ohm
now we know that
Part b)
Now at higher temperature we have
R = 0.98 ohm
now we know that
so we will have
2.
Answer:
Part a)
Part b)
Explanation:
Part a)
As we know that current density is defined as
now we have
Now we have
so we will have
Part b)
now we have
so we have
so we have
3 bulbs are in series and if the same 3 bulbs are in parallel with the same battery then the bulbs that are connected in parallel will be dimmer
<h3>What is power?</h3>
The rate of doing work is known as power. The Si unit of power is the watt.
Power =work/time
The mathematical expression for the electric power is as follows
P = VI
The same current flows through both bulbs when they are connected in series. A greater voltage drop across the bulb with the higher resistance will result in higher power dissipation and brightness. In the case of the parallel combination, the bulb will be dimmer
Thus, If the same three bulbs are connected in series and parallel with the same battery, the parallelly connected bulbs will be dimmer, therefore the correct option is A
Learn more about power from here
brainly.com/question/3854047
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Answer:
12 units
Explanation:
Original F = C q1q2/r^2 now change the parameters
New F = C 1/3 q1 2 q2 / (2r)^2
= 2/12 C q1q2/r^2 <=======the new force is 1/6 of original
1/6 * 72 = 12 units