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3 years ago

When a baseball hits a

1 answer:

3 0

The reaction force is the glove pushing against the ball because the reaction force would be the ball pushing onto the glove.

Hope that helps :)

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Which statement(s) accurately describe the conditions immediately before and after the firecracker explodes:

lidiya [134]

Answer:

Option C, The total momentum of the fragments is equal to the original momentum of the firecracker.

Explanation:

Kinetic energy of cracker cannot remain constant before and after explosion. It is so because in the process of burning and bursting some amount of kinetic energy is lost in the form of light and heat energy. While the total mass before and after the explosion remains constant due to which the momentum is conserved before and after the explosion

Hence, option C is correct

8 0

3 years ago

What is the force of a 24.52 kg Television dropped on Pluto (acceleration of 0.59 m/s2)

inna [77]

The force of gravity on the object is 14.47 N

Explanation:

The weight of an object (which is the force of gravity experienced by an object) at a certain location is given by

$F=mg$

where

m is the mass of the object

g is the acceleration of gravity at the location of the object

IN this problem, we have:

m = 24.52 kg (mass of the object)

$g=0.59 m/s^2$ (acceleration of gravity on Pluto)

Substituting, we find the force of gravity on the object:

$F=(24.52)(0.59)=14.47 N$

Learn more about forces and weight:

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#LearnwithBrainly

7 0

2 years ago

A ball thrown straight up into the air is found to be moving at 6.79 m/s after falling 1.87 m below its release point. Find the

MaRussiya [10]

Answer:

3.07 m/s

Explanation:

We know that from kinematics equation

$v^{2}=u^{2}+2as$ and here, a=g where v is the final velocity, u is the initial velocity, a is acceleration, s is the distance moved, g is acceleration due to gravity

Making u the subject then

$u=\sqrt {v^{2}-2gs}$

Substituting v for 6.79 m/s, s for 1.87 m and g as 9.81 m/s2 then

$u=\sqrt {6.79^{2}-(2\times 9.81\times 1.87)}=3.068338313 m/s\approx 3.07 m/s$

5 0

3 years ago

Question 11 of 11 | Page 11 of 11

KiRa [710]

Answer:

Decreases the time period of revolution

Explanation:

The time period of Cygnus X-1 orbiting a massive star is 5.6 days.

The orbital velocity of a planet is given by the formula,

v = √[GM/(R + h)]

In the case of rotational motion, v = (R +h)ω

ω = √[GM/(R + h)] /(R +h)

Where 'ω' is the angular velocity of the planet

The time period of rotational motion is,

T = 2π/ω

By substitution,

T = 2π(R +h)√[(R + h)/GM]

Hence, from the above equation, if the mass of the star is greater, the gravitational force between them is greater. This would reduce the time period of revolution of the planet.

3 0

3 years ago

What is a non contact force that attracts all objects to the centre of the earth

beks73 [17]

Answer:

Gravity. The weight-force or weight of an object is the force because of Gravity, which acts on the object attracting it towards the centre of the earth.

Hope this helps, 

 x

4 0

3 years ago