<h3><u>Given </u><u>:</u><u>-</u></h3>
A harmonic wave on a string is described by
- x is in cm and t is in seconds
<h3><u>Answer </u><u>1</u><u> </u><u>:</u><u>-</u></h3>
<u>Equation </u><u>for </u><u>travelling </u><u>wave </u><u>:</u><u>-</u>
<u>Equation</u><u> </u><u>for </u><u>stationary </u><u>wave </u><u>:</u><u>-</u>
<u>Given </u><u>equation </u><u>for </u><u>wave </u><u>:</u><u>-</u>
<u>On </u><u>comparing </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>,</u><u> </u><u>(</u><u>2</u><u>)</u><u> </u><u>and </u><u>(</u><u>3</u><u>)</u>
We can conclude that, Given wave represent travelling wave.
<h3>
<u>Answer </u><u>2</u><u> </u><u>:</u><u>-</u></h3>
From solution 1 , We can say that,
It is travelling from right to left direction
Hence, The direction of its propagation is right to left that is towards +x direction.
<h3>
<u>Answer </u><u>3</u><u> </u><u>:</u><u>-</u></h3>
Here, We have to find the wave period
<u>We </u><u>know </u><u>that</u><u>, </u>
Wave period = wavelength / velocity
<u>Wave </u><u>equation</u><u> </u><u>:</u><u>-</u>
<u>We </u><u>know </u><u>that</u><u>, </u>
<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>
<h3><u>Answer </u><u>4</u><u> </u><u>:</u><u>-</u></h3>
The wavelength of given wave
<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>
<h3><u>Answer </u><u>5</u><u> </u><u>:</u><u>-</u></h3>
We have wave equation
<u>Travelling </u><u>wave </u><u>equation </u><u>:</u><u>-</u>
<u>Therefore</u><u>, </u>
Amplitude of the wave particle
Hence, The amplitude of the particle is 0.1 cm