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3 years ago

Evaluate the expression for x = 4 1/3 9x + 4 A) 39 B) 40 C)43 D)52

2 answers:

8 0

The answer is C. 43

by substituting 4.3 for x you get
9(4.3)+4

Then multiply:

38.7+4

Then add:

42.7

Then round the number:

43

max2010maxim [7]3 years ago

4 0

C because 4 1/3= 13/3
Then (13/3)x9= 39
Lastly 39+4= 43

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Can someone please help me I really need help please help me thank you

Natalija [7]

Hey there! :)

Answer:

SA = 144 cm².

Step-by-step explanation:

Find the surface area by calculating the areas of each of the lateral sides and bases:

In this instance, the bases are triangles, so the formula A = 1/2(bh) will be used:

Bases:

A = 1/2(bh)

A = 1/2(4·3)

A = 1/2(12)

A = 6 cm².

There are two bases, so:

6 × 2 = 12 cm²

Find the areas of the lateral sides using A = l × w:

5 × 11 = 55 cm²

4 × 11 = 44 cm²

3 × 11 = 33 cm²

Add up all of the areas:

12 + 55 + 44 + 33 = 144 cm².

6 0

3 years ago

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Please solve this, What is the product of the binomials below? (d−1)(d+2)(d−3)

katrin [286]

I believe the answer is 3d+6

8 0

3 years ago

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Mathematically verify the outlier(s) in the data set using the 1.5 rule.

statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

$Q_1=\dfrac{24}{2}$

$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0

3 years ago

You roll a pair of six-sided number cubes, numbered 1 through 6. What is the probability of rolling two odd numbers? (Enter your

lbvjy [14]

Answer:

1/4 or 25%

Step-by-step explanation:

The probability for rolling an odd number is 50% or $\frac{1}{2}$ because there are 3 odd numbers, (1, 3, 5) and 6 total outcomes (1, 2, 3, 4, 5, 6). $\frac{3}{6} =\frac{1}{2}$

The probability for rolling two odd numbers in a row is

$\frac{1}{2} *\frac{1}{2} =\frac{1}{4}$

So, the probability of rolling an odd number twice is 25% or $\frac{1}{4}$ .

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3 years ago

Which equation shows equation shows y = - 3x +4 x + 4 is in standard form?

svet-max [94.6K]

Answer:

7x-y=-4

Step-by-step explanation:

Let me know if this right please :(

Hope it was is helpful for you :)

3 0

3 years ago