Describe the relationship between the perimeters of two similar rectangles and scale factor
1 answer:
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Answer:
I usually explain even in the answer.
So we use something called distance formula which is branched of Pythagorean theorem.
But we dont need to as it just makes it more complicated. We need to find split into 2 vectors, one vertical, and horizontal. The horizontal is 5 long.
The vertical is 1, you can find them by calculating how long is it and how tall.
Use pythogorean theorem from the formula and do 5^2+1^2 = c^2
25+1 = 26, so the answer is √26
I am pretty sure answer is right. Always take abolute value
<u>√26</u>
Answer:
r = (ab)/(a+b)
Step-by-step explanation:
Consider the attached sketch. The diagram shows base b at the bottom and base a at the top. The height of the trapezoid must be twice the radius. The point where the slant side of the trapezoid is tangent to the inscribed circle divides that slant side into two parts: lengths (a-r) and (b-r). The sum of these lengths is the length of the slant side, which is the hypotenuse of a right triangle with one leg equal to 2r and the other leg equal to (b-a).
Using the Pythagorean theorem, we can write the relation ...
((a-r) +(b-r))^2 = (2r)^2 +(b -a)^2
a^2 +2ab +b^2 -4r(a+b) +4r^2 = 4r^2 +b^2 -2ab +a^2
-4r(a+b) = -4ab . . . . . . . . subtract common terms from both sides, also -2ab
r = ab/(a+b) . . . . . . . . . divide by the coefficient of r
The radius of the inscribed circle in a right trapezoid is r = ab/(a+b).
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The graph in the second attachment shows a trapezoid with the radius calculated as above.
