Answer:
The required probability is 0.6517
Step-by-step explanation:
Consider the provided information.
North Catalina State University's students can be approximated by a normal model with mean 130 and standard deviation 8 points.
μ₁ = 130 and σ₁ = 8
Chapel Mountain University's students can be approximated by a normal model with mean 120 and standard deviation 10 points.
μ₂ = 120 and σ₂ = 10
As both schools have IQ scores which is normally distributed, distribution of this difference will also be normal with a mean of μ₁-μ₂ and standard deviation will be 
Therefore,
μ = 130-120=10

Now determine the probability of North Catalina State University student's IQ is at least 5 points higher than the Chapel Mountain University student's IQ:


Now by using the z table we find the z- score of -0.39 is 0.6517.
Hence, the required probability is 0.6517
(a-b)^2 = a^2-2ab+b^2
(8-5i)^2 = 8^2-2(8)(5i)+(5i)^2
= 64-80i+25i^2
i^2=-1
So
= 64-80i+25(-1)
=64-25-80i
= <em><u>39 - 80i</u></em>
which is your answer :)
Answer:
The correct answer is A
Step-by-step explanation:
<h2>
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Answer:
15
Step-by-step explanation:
f(x) = 3x -12 for x = 9
f(9) = 3(9) -12
27-12
15
Answer:
to what?
Step-by-step explanation: