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Setler79 [48]
4 years ago
8

What is the first quartile of this data set? 10, 11, 12, 15, 17, 19, 22, 24, 29, 33, 38

Mathematics
2 answers:
seraphim [82]4 years ago
5 0

Answer:

I believe it would  be 12

Step-by-step explanation:

brilliants [131]4 years ago
5 0
Yup the answer is 12
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��2222 is the diameter of a circle. The coordinates are �(−2, −3) and �(−12, −5). At what coordinate is the center of the circle
NARA [144]

Answer:

(-7,-4)

Step-by-step explanation:

iF YOU DRAW A CIRCLE ON PAPER USING THE COORDINATES YOU WILL SEE THE CENTRE OF THE CIRCLE.

HOPE IT HELPED.

7 0
3 years ago
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What is the initial value of the equation shown? (1 point) y = −7x − 6 −13 −7 −6 −1
Liula [17]

Answer:

-6

Step-by-step explanation:

The equation is y = -7x - 6.

The initial value is found when x = 0.

y = -7(0) - 6

y = 0 - 6

y = -6

6 0
2 years ago
Jake volunteers to help out his younger brother's basketball team in his free time. One of his tasks is to ensure that all the b
Aneli [31]

Answer:

The volume is 2140.98 inches³

Step-by-step explanation

The basketballs are spherical, and it is known that the volume of a sphere is

V = \frac{4}{3}\pi r^{3}

Where V is the volume of the ball and r is its radius


They tell us that the ball measures 8.8 inches wide. This means that its diameter is 8.8 inches.

It is known that the radius of a sphere is equal to half its diameter.

Therefore, the radius r of the ball is:

r = \frac{8.8}{2}

r = 4.4 inches.

Then, they tell us to consider that the walls of the ball are infinitely thin, which means that we should not take into account their thickness in the calculation of the volume.

We already have all the data we need, now we proceed to calculate the volume.

V = \frac{4}{3}\pi(4.4)^{3}\\V = 356.83 inches^{3}

Where V is the volume of only one of the balls

The volume of the six balls is V = 6 * 356.83 = 2140.98 inches³

Finally the volume is 2140.98 inches³

4 0
3 years ago
Read 2 more answers
1. What is (f⋅g)(x)?
nekit [7.7K]

Answer:

(f⋅g)(x)= x^7 + 9x^4 - 9x^3 -81

(f - g)(x) = x^3 - 6x^2 + 18x + 6x - 10

Step-by-step explanation:

For the first part of the question we have two functions

f(x) = x^4 -9

g(x) = x^3 + 9

If the expression refers to the multiplication of f and g, then:

(f⋅g)(x)= f (x)g(x)

So we multiply the function f(x) with the function g(x)

(f⋅g)(x)= (x^4 - 9)(x^3 + 9)

(f⋅g)(x)= x^7 + 9x^4 - 9x^3 -81

For the second part we have the functions:

f(x) = x^3 -2x^2 + 12x - 6\\\\g(x) = 4x^2 - 6x + 4

We wish to find (f - g) (x). We know that

(f - g)(x) = f(x) - g(x)\\\\(f - g)(x) = x^3 - 2x^2 + 12x - 6 - [4x^2 - 6x + 4]\\\\(f - g)(x) = x^3 - 2x^2 + 12x - 6 -4x^2 + 6x - 4

(f - g)(x) = x^3 - 6x^2 + 18x + 6x - 10

5 0
3 years ago
London can catch a lacrosse ball 13 times out of 15 times she is passed to. At the same rate,how many times will she catch the l
Blababa [14]

Answer:

65

Step-by-step explanation:

75/15=5

5*15=65

5 0
3 years ago
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