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3 years ago

Pepper Jamie has 12 picks. 1 out of every 4 pick is orange. The rest are green. How many picks are orange

Mathematics

2 answers:

Vlad [161]3 years ago

6 0

your answer would be 3 picks

kifflom [539]3 years ago

3 0

3 picks are orange.
12 divided by 4 = 3

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Mia and her 3 friends had £2468 between them. If her 3 friends all got 37% each of that the money. How much would be left for Mi

Ivan

Answer:

Mia had $1554.84

Step-by-step explanation:

100% = $2468

1% = $ 24.68

100 - 37 = 63%

63 % = 63 × $24.68

= $1554.84

6 0

3 years ago

Twenty-eight students reported how many email accounts they have. The dot plot below shows the data collected: A dot plot is sho

lisov135 [29]

I have attached a picture of the dot plot that you described. Each dot on the number line represents one answer. So, the number of dots above the number 4 tells us that there were 6 students who have 4 email accounts.

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2 years ago

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18

9*2
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3 years ago

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MAVERICK [17]

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3 0

3 years ago

A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran

Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0

3 years ago