Partition the set A into 4 subsets:
{1, 8}, {2, 7}, {3, 6}, and {4, 5},
each consisting of two integers whose sum is 9. If 5 integers are selected from A,
then by the Pigeonhole Principle at least two must be from the same subset. But
then the sum of these two integers is 9.
Probably uncomfortable,,,,
6(8)+b/6
48+b/6
b/6=-48
b=-48/6
b=-288
Answer:
Option B
Step-by-step explanation:
I solved in the picture
Hope this helps ^-^
The first number is 9 and the second number is 10. 10+9=10. 9*2=18 and 10 is 8 less than 18. All the requirements of the numbers are met.