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PolarNik [594]
3 years ago
5

brianne is three times as old as camila. four years from now she will be just two times ad old as camila. how old are brianna an

d camila now

Mathematics
2 answers:
lions [1.4K]3 years ago
8 0

12 and 4

Step-by-step explanation:

iren2701 [21]3 years ago
3 0
The answer to the question

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What is the area of the rhombus
erastova [34]

Answer:

12

Step-by-step explanation:

3 0
3 years ago
Please help solve much appreciated
DIA [1.3K]

Step-by-step explanation:

For the Cuboid, the formula will be:

Width x Height x Length

For the cylinder the volume formula will be:

\pi \:  \times  \:  {radius}^{2}  \times  \: length

7 0
3 years ago
Given the slope is -5 and the y-intercept is -2, what is the equation of the line in slope-intercept form? A y = 5x + 2 B y = -5
Law Incorporation [45]

Answer:

  B.  y = -5x -2

Step-by-step explanation:

Fill in the given values in the form ...

  y = (slope)x + (y-intercept)

  y = -5x +(-2)

  y = -5x -2 . . . . simplify; matches choice B

8 0
3 years ago
Alyssa is factoring the following expression p∆2-8p-9. She said the answer is (p-1) (p +9). Is she correct? If not, explain her
Lesechka [4]

Answer:

Step-by-step explanation:

p^2-8p-9

factor out the trinomial

(p-9)(p+1)

Therefore, she's incorrect. Because (p-1)(p+9)=p^2-p+9p-9=p^2+8p-9 and that's different from p^2-8p-9.

5 0
3 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
4 years ago
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