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yulyashka [42]
4 years ago
3

A rectangular deck is 12 ft by 14 ft. When the length and width are increased by the same amount, the area becomes 288 sq. ft. B

y how much were the dimensions increased?
A-2ft
B-4ft
C-8ft
D-10ft
Mathematics
2 answers:
Marina CMI [18]4 years ago
8 0

Answer:

B 4ft

Step-by-step explanation:

Took the test on edg.

Neporo4naja [7]4 years ago
7 0
X=amount increased

newlegnth=legnth+x=14+x
newwidth=width+x=12+x

area=legnth times width
newarea=newlegnth times newwidth

288=newarea

(14+x)(12+x)=288
168+26x+x^2=288
x^2+26x+168=288
minus 288 from both sides
x^2+26x-120=0
factor
find what 2 numbers multiply to get -120 and add to get 26
-4 and 30
(x-4)(x+30)=0
set each to zero

x-4=0
x=4

x+30=0
x=-30
wrong, if it was increased by -30, the side legnths would be -18 and -16, and negative measures are not allowed


x=4

answer is increased each side by 4 feet

B
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The waiting time to a roller coaster is 20 minutes when 150 people are in line. How long is the waiting time when 240 people are
scoray [572]
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I hope I did that right! And if I did, I hope that helped!
5 0
3 years ago
Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.
fgiga [73]

Answer:

  • QN = 3√7
  • OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

  DQ = (3 units)·3 = 9 units

  KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

  KI² = KO² +OI²

  4² = 3² +OI²

  OI = √(16 -9)

  OI = √7

  QN = 3·OI = 3√7

8 0
3 years ago
Pls help middle school math and picture question
Ira Lisetskai [31]
Distance is 10 united
5 0
3 years ago
Read 2 more answers
A student is selling small and large frozen pizzas for a school fund-raiser.
dexar [7]

System of equations:

We'll need one equation for the amount of pizzas, and another for the total cost of the pizzas. In this case, x will represent small pizzas, and y will represent large pizzas.

3x + 4y = 100

x + y = 30

Solving the system of equations:

First, we need to solve for one variable in one equation.

x + y = 30

x = 30 - y

Then, we'll take our equation that is solved for x and plug it into the other equation from above.

3(30 - y) + 4y = 100

Next, we solve for y.

90 - 3y + 4y = 100

90 + y = 100

y = 10

Finally, we take our value for y and plug it back in to the very first equation and solve for x.

x = 30 - 10

x = 20

Answer:

The student has sold 10 large pizzas and 20 small pizzas.

Hope this helps!! :)

6 0
3 years ago
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