3x^2y^3+5x^3y^3-6+x^3y^2-2
= (3x^2y^3+5x^3y^3+x^3y^2)-(6+2)
= x^2y^2(3y+5xy+x)-8.
The final answer is x^2y^2(3y+5xy+x)-8~
Answer:
5.3-1.45=3.85
Step-by-step explanation:
she has 3.85 miles left to go because she already ran 1.45 and if you subtract that from the 5.3 you get 3.85 left to run.
Answer:
16/33
Step-by-step explanation:
12C4(total possible outcomes)=495
Since there are 6 married couples there must be 6*[2C2×10C2]=270
must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255
the no of groupings with no married couples 495-255 =240
probability=no of favourable outcomes /no of possible outcome
probability=240/495= 16/33
