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a+b= 8+24=32
Ab=8 x 24= 192
B/a= 24:8=3
(a+b)²=(8+24)² =64+576+384= 1024
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Assume the smaller one is x, then the other ones will be x+2 and x+4
x(x+2) + 2 = 5(x+4)
x^2 + 2x - 5x - 18 = 0
-> x^2 - 3x - 18 = 0
-> (x-6)(x+3) = 0
-> x = 6 or -3, since x must be positive, then x = 6
So the numbers are: 6, 8, 10
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Step-by-step explanation:
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Answer:
10 and 15
Step-by-step explanation:
Let 'x' and 'y' are the numbers we need to find.
x + y = 25 (two numbers whose sum is 25)
(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)
The solutions of the this system of equations are the numbers we need to find.
x = 25 - y
1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y
6y + 6(25-y) = (25-y)y
6y + 150 - 6y = 25y - (y^2)
y^2 - 25y + 150 = 0 quadratic equation has 2 solutions
y1 = 15
y2 = 10
Thus we have
:
First solution: for y = 15, x = 25 - 15 = 10
Second solution: for y = 10, x = 25 - 10 = 15
The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).
