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Ede4ka [16]
2 years ago
13

Who has the right to levy taxes on the income of individuals and businesses by the ruling of the 16th Amendment of the Constitut

ion that was signed into law in 1913?
A. Congress
B. The governor
C. The president
D. The Supreme Court
Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
5 0
Congress can levy taxes.
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Mary rolls two dice. She adds the numbers on the two dice. What is the chance of this sum being twelve?
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10%

Step-by-step explanation:

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The midpoint between -7 and 8 is 1/2 t or f
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Answer:

  True

Step-by-step explanation:

The midpoint is the average of the values:

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g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
3 years ago
True or false: (a) If A2 is defined then A is necessarily square. (b) If AB and BA are defined then A and Bare square. (c) If AB
andrew-mc [135]

(a) True. Suppose A is a not a square matrix, with m rows and n columns. Then A² is not defined, because you can't multiply an m×n matrix by another m×n matrix.

(b) False. As an example, consider the matrices

A_{3\times2} = \begin{bmatrix}1&0\\0&1\\0&0\end{bmatrix}

B_{2\times3} = \begin{bmatrix}-1&0&1\\0&0&1\end{bmatrix}

Then both AB and BA are defined, with

AB_{3\times3} = \begin{bmatrix}-1&0&1\\0&0&1\\0&0&0\end{bmatrix}

BA_{2\times2} = \begin{bmatrix}-1&0\\0&0\end{bmatrix}

In general, you can multiply any m×n by any n×m matrix.

(c) True. Multiplying a m×n matrix by a n×m matrix always yields a m×m matrix, and multiplying a n×m matrix by a m×n matrix always yields a n×n matrix.

4 0
2 years ago
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