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Gala2k [10]
3 years ago
11

What would 897,100 be if rounded to the nearest ten thousand?

Mathematics
2 answers:
tamaranim1 [39]3 years ago
7 0

Answer is 900,000.


<em>Explanation;</em>

To round off the numbers we should know the place values of the digis. The place values of the digits in 897,100 are as follows


8                                           9                        7                   1                0        0

↑                                           ↑                        ↑                    ↑                ↑        ↑

Hundred thousands   Ten thousands   Thousands   Hundreds   Tens   ones


To round off nearest ten thousand we should look at the digit after the ten thousands place means thousands place.


If the digit is thousands place is smaller than 5, the ten thousands place will not be changed. But that digit is equal or larger than 5, 1 should be added to the ten thousands place.


The digit in thousands place is 7. It is greater than 5. Hence, 1 should be added to the digit in ten thousands place. Then 1 + 9 = 10. Hence, answer is 100,000.




Finger [1]3 years ago
6 0
90,000

the reason is because look at the 1,000 place that rounds the 10,000 place to 0 and carries the 1 over to the 100,000 place


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kobusy [5.1K]

Answer:

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

Step-by-step explanation:

Given that, a storage shade is be built in the shape of a box with a square base.

Let the height of the box be h and the length of one side of the square base be x.

The area of the square base is = side²

                                                    =x²

The volume of the box is = area of the base × height

                                          =x²h

According to the problem,

x²h=686

\Rightarrow h=\frac{686}{x^2} .......(1)

The concrete for the base costs $5 per square foot.

The material for the base costs =$ 5x²

The material for the roof costs $9 per square foot.

The material cost for roof is =$9x²

The material for the sides costs $3.50  per square foot.

The material cost for sides =$(3.50× 4xh )

                                             =$14xh

Total cost =$(5x²+9x²+14xh)

                =$(14x²+14 xh)

Let

C = 14x²+14 xh

Putting h=\frac{686}{x^2}

C=14x^2+14 x.\frac{686}{x^2}

\Rightarrow C=14x^2+\frac{9604}{x}

Differentiating with respect to x

C'= 28x-\frac{9604}{x^2}

Again differentiating with respect to x

C''= 28+\frac{19208}{x^2}

To find the dimension set C'=0

28x-\frac{9604}{x^2}=0

\Rightarrow 28x=\frac{9604}{x^2}

\Rightarrow x^3=\frac{9604}{28}

\Rightarrow x=7

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C''|_{x=7}= 28+\frac{19208}{7^2}>0

Since at x=7, C''>0, So at x=7 , The cost of material will be minimum.

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Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

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