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Sedbober [7]
3 years ago
14

You randomly select 2 marbles from a mug containing 7 blue marbles, 3 red marbles, and 2 white marbles. How many times greater i

s the probability of selecting one blue marble and then one red marble when you do not replace the first marble before selecting the second marble than when you do replace the first marble before selecting the second marble? Express the answer as a fraction.
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

Scenario 1: w/o replacement: P(blue, then red) = (7/12)(3/11) = 7/44

Scenario 2: w/ replacement:  P(blue, then red) = (7/12)(3/12) = 7/48

Ratio of Probability #1 to Probability # 2 = 48/44 = 12/11, i.e. Prob # 1 is 1.0909... times Prob # 2

Step-by-step explanation:

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Which of the following is not equal to sin⁡(-230°)?
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From trigonometry we know that:

if sin(\theta)=sin(\alpha)

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This can be rewritten in degrees as:

\theta=n(180^{\circ})+(-1)^n\alpha.............(Equation 1)

Now, in our case, \alpha=-230^{\circ}

Therefore, (Equation 1) can be written as:

\theta=n(180^{\circ})+(-1)^n(-230^{\circ})..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of \theta that match.

For n=2, (Equation 2) gives us: \theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}.

Thus, sin(230^{\circ})=sin(130^{\circ})

Now, we know that: -sin(-50^{\circ})=sin(50^{\circ})

Let n=-1, then:

\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}

Thus, sin(-230^{\circ})=-sin(-50^{\circ})

Likewise, sin(-230^{\circ})=sin(50^{\circ})

Only the last option sin(-50^{\circ}) will never match sin(-230^{\circ}) because no integral value of n will ever give \theta=-50^{\circ}

Thus the last option is the correct option.

3 0
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Step-by-step explanation:

Hope this helps

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Answer:

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