The correct option is "d".
Given that L = 0.8T²
length of pendulum = 30ft
L= 0.8T²
30 = 0.8T²
T² = 30 / 0.8
T² = 37.5
T = √37.5 = 6.1 seconds
<span>So, 6.1 is the closest to the period in seconds for a pendulum that is 30 ft long.</span>
Answer: 6.25 or 6 
Step-by-step explanation:
Lets do a pro gamer move and convert all fractions to decimals.
We now have 1+1+1.25+1.5+1.5.
From there on we simply do addition.
1+1+1.25+1.5+1.5=6.25
We get 6.25 or 6
Answer:
False
Step-by-step explanation:
4 cos^4 (4x)-3 = 0
Substitute into the equation
4 cos^4 (4pi/24)-3 = 0
4 cos^4 (pi/6)-3 = 0
Take the cos pi/6
4 ( sqrt(3)/2) ^4 -3 =0
Take it to the 4th power
4 ( 9/16) -3 =0
9/4 -3 =0
9/4 - 12/4 = 0
-3/4 =0
False
Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
