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Valentin [98]
3 years ago
14

The measure of central angle QRS is radians. What is the area of the shaded sector? 36 72 144 324

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0
The picture in the attached figure

we know that

the angle measurement of central angle QRS is less than pi radians


area of the circle=pi*r²
for r=18 units
area of the circle=pi*18²------> 324*pi units²
area of ​​the half of a circle=324*pi/2-----> 162*pi units²
area of ​​a quarter of a circle=324*pi/4----> 81*pi units²

<span>analyzing the graph we can say that the shaded area is smaller than the area of ​​the middle of a circle but it is larger than the area of ​​a quarter of a circle
</span>so
the area of the shaded sector < 162*pi units²
and
the area of the shaded sector > 81*pi units²

therefore
the answer must be 144*pi units²

ludmilkaskok [199]3 years ago
4 0

\frac{7128}{14}We are given radius of the given circle = 18 units.

The shown angle of the sector is a little smaller than π radians.

Let us take it π radians.

We know formula for area of a sector is =\frac{1}{2}r^2*angle \ of \ the \ sector.

We took angle = π

Plugging values in formula, we get

Area of the sector is =\frac{1}{2}(18^2 \times \pi)

=\frac{1}{2}(324 \times \pi)

= 162π

The nearest value of 162π in the given options is 144π .

Therefore, area of the shaded sector is 144π.


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Is 0.270 greater than 0.27 answer quick this us to double check
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Let H be the set of all polynomials having degree at most 4 and rational coefficients. Determine whether H is a vector space. If
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Yes. It is a vector space over the field of rational numbers \mathbb{Q}

Step-by-step explanation:

An element p of the set H has the form

p(x)=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4}

where a_{0},a_{1},a_{2},a_{3},a_{4} are rational coefficients.

The operations of addition and scalar multiplication are defined as follows:

p(x)+q(x)=(a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+x_{4}x^4)+(b_{0}+b_{1}x+b_{2}x^{2}+b_{3}x^{3}+b_{4}x^{4})=(a_{0}+b_{0})+(a_{1}+b_{1})x+(a_{2}+b_{2})x^{2}+(a_{3}+b_{3})x^{3}+(a_{4}+b_{4})x^{4}

\lambda p(x)=\lambda (a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4})=\lambda a_{0}+\lambda a_{1}x+\lambda a_{2}x^{2}+\lambda a_{3}x^{3}+\lambda a_{4}x^{4}

The properties that H, together the operations of vector addition and scalar multiplication,  must satisfy are:

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This is not difficult with the definitions given. The most important part is to show that H has a additive identity, which is the zero polynomial, that is closed under vector addition and scalar multiplication. This last properties comes from the fact that \mathbb{Q} is a field, then it is closed under sum and multiplication.

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