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lorasvet [3.4K]
3 years ago
12

Help me what the answers

Mathematics
1 answer:
Marina86 [1]3 years ago
3 0
If it is perimeter do this L+W×2
If it's area do this L×W
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Two sides of a triangle have lengths 10 and 18. Which inequalities describe the possible lengths for the third side x?
puteri [66]
Let with X is denoted the length of the third side.
For a triangle the following statements must be true:
The sum<span> of the </span>lengths<span> of any two sides of a </span>triangle<span> is greater than the </span>length<span> of the third side.
 This means that this inequality can be written: X<10+18 ,X<28

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20 adults and 15 children are going to attend a musical evening. The organizers have arranged the tables in such a way that ther
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Answer:

Step-by-step explanation:

20 + 15 = 35 . Now you need to list the factor of 35:    1, 5, 7, 35 pickt the smallest factor.

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Tim fisher received a 1200 discount loan to purchase a computer the loan was offered at 18% for 180 days find the interest in do
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6 0
3 years ago
You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy.
Alchen [17]

Answer:

A. 3 possible combinations

B. 8 4-ounce's bags and 3 3-ounce's bags

C. 2 4-ounce's bags and 11 3-ounce's bags

D. 8 4-ounce's bags and 3 3-ounce's bags

E. All solutions offer the same revenue.

Step-by-step explanation:

You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy. Let x be the number of 4 ounce bags and y be the number of 3 ounce bags. Then

4x+3y=41.

A. Find all integer solutions:

  • When x=0, then 3y=41 - impossible, because 41 is not divisible by 3.
  • When x=1, then 3y=37 - impossible, because 37 is not divisible by 3.
  • When x=2, then 3y=33, y=11 - possible.
  • When x=3, then 3y=29 - impossible, because 29 is not divisible by 3.
  • When x=4, then 3y=25 - impossible, because 25 is not divisible by 3.
  • When x=5, then 3y=21, y=7 - possible.
  • When x=6, then 3y=17 - impossible, because 17 is not divisible by 3.
  • When x=7, then 3y=13 - impossible, because 13 is not divisible by 3.
  • When x=8, then 3y=9, y=3 - possible.
  • When x=9, then 3y=5 - impossible, because 5 is not divisible by 3.
  • When x=10, then 3y=1 - impossible, because 1 is not divisible by 3.

You get 3 possible combinations.

B. 1. 2 + 11 = 13,

2. 5 + 7 = 12,

3. 8 + 3 = 11.

The minimal number of bags is 11.

C. 1. 2·7+11·5=69 cents

2. 5·7+7·5=70 cents

3. 8·7+3·5=71 cents

The cheapest is 1st solution.

D. 1. 2·6+11·5=67 cents

2. 5·6+7·5=65 cents

3. 8·6+3·5=63 cents

The cheapest is 3rd solution.

E. 1. 2·2+11·1.50=$20.50

2. 5·2+7·1.50=$20.50

3. 8·2+3·1.50=$20.50

All solutions offer the same revenue.

5 0
3 years ago
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