Ask question

Ask question

All categories

Lubov Fominskaja [6]

3 years ago

5

Need an answer thanks

2 answers:

Anna007 [38]3 years ago

8 0

Answer:

37

Step-by-step explanation:

jarptica [38.1K]3 years ago

5 0

Answer:

37

Step-by-step explanation:

Since the length of AB is 6 and BD is 31 So AD is 6+31=37

You might be interested in

HELPPPPPPPPPPPPPPPPPPPPPPPP

nlexa [21]

I believe the answer is C, x-3.

4 0

2 years ago

____ [38]

Answer:

y = 5x+3

Step-by-step explanation:

a general line is represented by the equation:

y = mx + n

a line with m=5, that goes through (-1,-2), should satisfy the equation:

-2 = 5×(-1) + n

this is because any point on the line, satisfies it's equation.

from this we get n = 3, hence our answer

4 0

1 year ago

Jana ran the first 3 and a half miles of a 5 mile race in 1 3rd of an hour. what was her average rate, in mph, for the first par

Lisa [10]

Answer:

always try to draw a diagram first

Step-by-step explanation:

Jana ran The first 3.5 miles in 1/3 of an hour. remember the problem tells us that we want our answer in miles per hour or mph. so we have to set up our problem so that our units match in the end. The diagram above shows 3.5 mi over 1/3 hour. so we must divide 3.5 miles by 1/3 hour

note:

$3 \frac{1}{2} mi = \frac{7mi}{2}$

therefore

$\frac{7mi}{2} \: \div \: \frac{1hr}{3} =$

$\frac{7mi}{2} \times \frac{3}{1hr} = \frac{21mi}{2hr} = 10 \frac{1}{2} \frac{mi}{hr}$

7 0

2 years ago

Which of the following illustrates the truth value of the given conditional statement?

AleksandrR [38]

Answer:

it looks like its c

Step-by-step explanation:

sorry if im wrong

5 0

2 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t

damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that $\mu = 3$

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472$

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0

2 years ago