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levacccp [35]
3 years ago
6

Find the midpoint of (0,4) and (-4,-12)

Mathematics
1 answer:
ankoles [38]3 years ago
5 0
The answer is (-2,-4) to solve this you need to add the X’s and divide by 2 and that will be your X for the midpoint, you do the same with the Y’s to find the y for your midpoint
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Answer:

DON'T LOOK AT THE PICTURE!!

Step-by-step explanation:

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3 years ago
Solve for w: k = 3pw<br> please help i have no clue
navik [9.2K]

Answer:

w = \dfrac{k}{3p}

Step-by-step explanation:

k = 3pw

Step 1: switch sides.

3pw = k

Step 2: Since you want w alone, and w is being multiplied by 3p, divide both sides by 3p.

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• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando
antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:  

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$ Z =  \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}  $

$ Z =  \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}  $

$ Z =  \frac{- 0.09}{ 0.048989 }  $

Z = - 1.84

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p >  α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0
3 years ago
If the cost of a raffle ticket is $2, which of the following expressions could be used to represent the cost of m tickets? 2m 2
Bingel [31]
It would be 2m because each ticket is 2 dollars and then you have to multiply it by the number of tickets you are buying M
6 0
3 years ago
-What is the future value of a $1,000 annuity payment over five years if interest rates are 9 percent?
Flauer [41]

Answer:

9% = 450

10% = 500

8% = 400

Step-by-step explanation:

6 0
3 years ago
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