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Otrada [13]
3 years ago
15

What is the answer to this problem? 2 1/3 + 3 1/3 = ?

Mathematics
2 answers:
Sever21 [200]3 years ago
7 0

Answer:

5 2/3

Step-by-step explanation:

elena-s [515]3 years ago
6 0
5 2/thirds or 5 2/3 hope this helps!
You might be interested in
Simplify (5n^4)^−3. Assume n ≠ 0.
tekilochka [14]
Since the exponent (-3) is negative, flip the expression to: 1/(5n^4)^3.

Notice how the negative exponent becomes positive as you flip it.

Now evaluate the powers in the denominator: 1/((5^3)(n^4)^3

I separated the constant (5) from the variable (n) to show you how the powers are evaluated.

1/(5x5x5)(nxnxnxn)(nxnxnxn)(nxnxnxn)
—-> the power four means that there are 4 multiples of n in the parentheses. The power 3 corresponds to how many groups.

1/(125)(n^12)

= 1/125n^12
6 0
3 years ago
Create 3 angle that will create a triangle. Remember, a triangle has to have a sum of 180 degrees. I then want you to respond ba
levacccp [35]

Answer:

60,60,60

90, 45,45

Step-by-step explanation:

I'll name them Jim and Jam

:)

5 0
3 years ago
Hats and mittens are on sale at the store! One woman was able to buy 5 hats and 4 pairs of mittens for $30.
morpeh [17]

The price of one hat is $2 and price of one pair of mittens is $5.

Step-by-step explanation:

Let,

Price of one hat = x

Price of one pair of mittens = y

According to given statement;

5x+4y=30      Eqn 1

2x+3y=19       Eqn 2

Multiplying Eqn 1 by 2

2(5x+4y=30)\\10x+8y=60\ \ \ \ Eqn\ 3

Multiplying Eqn 2 by 5

5(2x+3y=19)\\10x+15y=95\ \ \ \ Eqn\ 4

Subtracting Eqn 3 from Eqn 4

(10x+15y)-(10x+8y)=95-60\\10x+15y-10x-8y=35\\7y=35\\

Dividing both sides by 7

\frac{7y}{7}=\frac{35}{7}\\y=5

Putting y=5 in Eqn 1

5x+4(5)=30\\5x+20=30\\5x=30-20\\5x=10

Dividing both sides by 5

\frac{5x}{5}=\frac{10}{2}\\x=2

The price of one hat is $2 and price of one pair of mittens is $5.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/11145277
  • brainly.com/question/11150876

#LearnwithBrainly

4 0
3 years ago
Jamie had 4 fith of a spool of twin.He then used half of a spool of twin to make freindship knots.Heclaims to have 3 tenth of th
Rom4ik [11]
Jamie's claim isn't reasonable. This is because half of 4/5 is 4/10 and if you simplify it, it is 2/5.
6 0
3 years ago
The mean of a population is 74 and the standard deviation is 16. The shape of the population is unknown. Determine the probabili
uysha [10]

Answer:

(a) P(\bar X \geq 76) = 0.2327

(b) P(73 < \bar X < 75) = 0.5035

(c) P(\bar X < 74.8) = 0.77035

Step-by-step explanation:

We are given that the mean of a population is 74 and the standard deviation is 16.

Assuming the data follows normal distribution.

<u><em>Let </em></u>\bar X<u><em> = sample mean </em></u>

The z-score probability distribution for sample mean is given by;

                         Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 74

            \sigma = standard deviation = 16

            n = sample size

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

(a) Probability that a random sample of size 34 yielding a sample mean of 76 or more is given by = P(\bar X \geq 76)

   P(\bar X \geq 76) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{76-74}{\frac{16}{\sqrt{34} } } ) = P(Z \geq 0.73) = 1 - P(Z < 0.73)

                                                 = 1 - 0.7673 = <u>0.2327</u>

<em>The above probability is calculated by looking at the value of x = 0.73 in the z table which has an area of 0.7673.</em>

<em />

(b) Probability that a random sample of size 120 yielding a sample mean of between 73 and 75 is given by = P(73 < \bar X < 75) = P(\bar X < 75) - P(\bar X \leq 73)

   

   P(\bar X < 75) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{75-74}{\frac{16}{\sqrt{120} } } ) = P(Z < 0.68) = 0.75175

   P(\bar X \leq 73) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{73-74}{\frac{16}{\sqrt{120} } } ) = P(Z \leq -0.68) =1 - P(Z < 0.68)

                                                 = 1 - 0.75175 = 0.24825

Therefore, P(73 < \bar X < 75) = 0.75175 - 0.24825 = <u>0.5035</u>

<em>The above probability is calculated by looking at the value of x = 0.68 in the z table which has an area of 0.75175.</em>

<em />

(c) Probability that a random sample of size 218 yielding a sample mean of less than 74.8 is given by = P(\bar X < 74.8)

   

   P(\bar X < 74.8) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{74.8-74}{\frac{16}{\sqrt{218} } } ) = P(Z < 0.74) = <u>0.77035</u>

<em>The above probability is calculated by looking at the value of x = 0.74 in the z table which has an area of 0.77035.</em>

7 0
3 years ago
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