No no dont take any bad decisions god know what to do there is a bright future in front of u
Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let = <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>
The z-score probability distribution for the sample mean is given by;
Z = ~ N(0,1)
where, = population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P( > 259 cm)
P( > 259 cm) = P( > ) = P(Z > -0.39) = P(Z < 0.39)
= <u>0.65173</u>
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
291.87 is rational since the last (decimal) numbers aren't repeating.
If it was repeating (291.877777...) it would be irrational.
Step-by-step explanation:
first, distribute 7 to 6m (this means 7 • 6m)
7 • 6m = 42m
then distribute 7 to 7 (which is 7 • 7)
7 • 7 = 49
your simplified expression is <u>42m + 49</u>. i hope this helps! have a great day <3
$ per min is a rate. you multiple by minutes to get dollars.
A = 10x
B = 5x + 20
set them equal to find minutes, x.
10x = 5x + 20
10x - 5x = 20
5x = 20
x = 4