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3 years ago

Select the correct answer from each drop-down menu.

Chemistry

1 answer:

Grace [21]3 years ago

6 0

Answer:

An SCl2 molecule has polar bonds and a bent angular molecular shape. As a result, an SCl2 molecule is polar.

Explanation:

It is a covalent compound made up of angular molecules that contain two chlorine atoms attached to one sulfur atom. Sulfur undergoes sp3 hybridization and has two pairs of nonbonding electrons. Given their geometry and the difference in electronegativity between chlorine and sulfur, they are molecules with a marked polar character. The bond angle between the sulfur atom and the two chlorine atoms is 109.5°, since the two vectors are of equal intensity but their directions do not coincide; if they are added vectorially, they do not cancel each other out, making the molecule polar.

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8. Which of the following is TRUE about limiting and excess reactants?

Ivahew [28]

B. The limiting reactant determines the max amount of product that can be formed

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3 years ago

Explain what might happen to tundra animals, such as polar bears, as earth's climate warms. pls explain

SCORPION-xisa [38]

Answer:

They will die.

Explanation:

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3 years ago

What is the maximum number of moles of NaCl that can be produced from the reaction of 5.6 mol Na and 4.7 mol CI2?

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Answer:

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Explanation:

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3 years ago

The CRC Handbook, a large reference book of chemical and physical data, lists two isotopes of indium (). The atomic mass of 4.28

ivanzaharov [21]

Answer: The mass of second isotope of indium is 114.904 amu

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

.....(1)

Let the mass of isotope 2 of indium be 'x'

For isotope 1:

Mass of isotope 1 = 112.904 amu

Percentage abundance of isotope 1 = 4.28 %

Fractional abundance of isotope 1 = 0.0428

For isotope 2:

Mass of isotope 2 = x amu

Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %

Fractional abundance of isotope 2 = 0.9572

Average atomic mass of indium = 114.818 amu

Putting values in equation 1, we get:

$114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu$

Hence, the mass of second isotope of indium is 114.904 amu

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3 years ago

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Flauer [41]

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3 years ago

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