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hammer [34]
3 years ago
14

How many liters of oxygen gas are there in 45.0g O, at 0 degrees C and 1 atm of pressure? make sure to round to the correct numb

er of
sig figs and to include the unit in your final answer
Chemistry
1 answer:
ZanzabumX [31]3 years ago
3 0

Answer:

You can use the pdf to help you

Explanation:

Download pdf
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Atoms of metallic elements tend to...
lara31 [8.8K]

The answer is: lose electrons and form positive ions.

Most metals have strong metallic bond, because of strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).

For example, magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.  

Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.  

3 0
3 years ago
A Is an ecosystem that is covered with water for at least part of the year
ruslelena [56]
It could be a tide pool but this is pretty vague
4 0
4 years ago
2NBr3 + 3NaOH = N2 +3NaBr + 3HOBr
bija089 [108]
The theoretical proportion is given by the balanced chemical equation:

2 mol NBr / 3 mol  Na OH

Then x mol NaOH / 40 mol NBr3 = 3mol NaOH/2 mol NBr3

Solve for x, x = 40 * 3/2 = 60 mol NaOH.

Given that there are 48 mol NaOH (less than 60) this is the limitant reactant and the other is the excess reactant.

Answer: NBr3..

 
6 0
3 years ago
Read 2 more answers
What is the temperature of the freezing point of water in celsius?
LuckyWell [14K]
It is 0 gradus in celcius
6 0
3 years ago
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Hypochlorous acid decays in the presence of ultraviolet radiation. Assume that degradation occurs accord- ing to first-order kin
Dennis_Churaev [7]

Answer:

35.75 days

Explanation:

From the given information:

For first-order kinetics, the rate law can be expressed as:

\mathsf{In \dfrac{C}{C_o} = -kt}

Given that:

the rate degradation constant = 0.12 / day

current concentration C = 0.05 mg/L

initial concentration C₀ = 3.65 mg/L

\mathsf{In( \dfrac{0.05}{3.65})= -(0.12) t}

㏑(0.01369863014) = -(0.12) t

-4.29 = -(0.12)

t = -4.29/-0.12

t = 35.75 days

3 0
3 years ago
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