The amount of nitrogen oxide in the air sample is determined as 7.01 ppb.
<h3>
Amount of Nitrogen oxide in the air</h3>
The amount of Nitrogen oxide (NO2) in the air in parts per billion (ppb) is calculated as follows;
12 micrograms of NO2 = 12 μg = 12 x 10⁻⁶ g
PV = nRT
V = nRT/P
Where;
- V is volume of NO2 gas
- n is number of moles of NO2 gas
- T is temperature = 40 C = 313 K
n = m/M
M = molar mass of NO2 = 46
n = 12 x 10⁻⁶/46
n = 2.73 x 10⁻⁷ mole
V = (2.73 x 10⁻⁷ x 0.082057 x 313)/(1)
V = 7.01 x 10⁻⁶ L
V = 7.01 x 10⁻⁹ m³
<h3>Amount of NO2 In parts per billion</h3>
= (Volume of NO2)/(volume of air) x 10⁹
= (7.01 x 10⁻⁹)/(1) x 10⁹
= 7.01 ppb
Thus, the amount of nitrogen oxide in the air sample is determined as 7.01 ppb.
Learn more about nitrogen oxide here: brainly.com/question/13629381
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Your answer would be they have mobile ions in solution.
Answer:
RbOH → Rb⁺ + OH⁻
As the hydroxide can gives the OH⁻ in water, it is considered as an Arrhenius's base
Explanation:
Arrhenius theory states that a compound is considered a base, if the compound can generate OH⁻ ions in aqueous solution.
Our compound is the RbOH.
When it is put in water, i can dissociate like this:
RbOH → Rb⁺ + OH⁻
As the hydroxide can gives the OH⁻ in water, it is considered as an Arrhenius's base
Heya!!!
Answer to your question:
A catalyst is ______
B. Not used up in a reaction.
Catalyst do not change the amount of reactants or products or itself get used but it just change the rate of reaction.
Hope it helps *_*
Answer:
B
Explanation:
it depends if the weather was cold but ummm they warm and cold air would mix and turn story and watch out tornadoes could also happen
