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blsea [12.9K]
3 years ago
15

Find the equation of a line that passes through the point (-5,4) and is perpendicular to 6x-36y

Mathematics
1 answer:
____ [38]3 years ago
6 0

<u>Answer:</u>

y =  - 6x  - 2

<u>Explanation</u>

The given line is

6x - 36y = k

where k is the missing constant from the given equation( this has no effect on the solution in anyway)

We solve for y to get;

y =  \frac{1}{6}x - \frac{k}{36}

The slope of this line after comparing to

y=mx+c is

m =  \frac{1}{6}

The negative reciprocal is m=-6

The equation of the required line that passes through (-5,4) is given by

y  - 4 = - 6(x -  - 5)

We multiply through by 6 to get:

y - 4 =  - 6x - 30

We expand to get;

y =  - 6x - 26

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What is the equation of this graphed line?
barxatty [35]

Answer:

y=-\frac{1}{3}x-5

Step-by-step explanation:

Given:

The two points on the line are:

(x_1,y_1)=(-6,-3)\\(x_2,y_2)=(6,-7)

Now, for a line with two points on it, the slope of the line is given as:

m=\frac{y_2-y_1}{x_2-x_1}

For the points (x_1,y_1)=(-6,-3)\ and\ (x_2,y_2)=(6,-7), slope is:

m=\frac{-7-(-3)}{6-(-6)}\\m=\frac{-7+3}{6+6}\\m=\frac{-4}{12}=-\frac{1}{3}

Now, for a line with slope 'm' and a point (x_1,y_1) on it is given as:

y-y_1=m(x-x_1)

Plug in all the values and determine the equation of the line. This gives,

y-(-3)=-\frac{1}{3}(x-(-6))\\\\y+3=-\frac{1}{3}(x+6)\\\\y+3=-\frac{1}{3}x-\frac{1}{3}\times 6\\\\y+3=-\frac{1}{3}x-2\\\\y=-\frac{1}{3}x-2-3\\\\y=-\frac{1}{3}x-5

Therefore, the equation of the line is:

y=-\frac{1}{3}x-5

4 0
3 years ago
In 2008 election there was 28 blue states and 22 red states express the red and blue states as fractions in lowest terms of the
Basile [38]
Let's start with the blue states. Out of 50 states, 28 of them were blue.
Therefore, the fraction would be 28/50. Let's reduce it.
28/50=14/25 --> these are the lowest terms for this fraction
Use a calculator to find the decimal solution --> 14/25= .56

Now, let's do the red states. Out of the 50 states, 22 of them were blue.
22/50=11/25 --> lowest terms
Use a calculator --> 11/25= .43
8 0
4 years ago
Simplify: 6v+v+1 learned at beggining of year btw
Readme [11.4K]

Answer:

7v +1

Step-by-step explanation:

6v+v+1

Combine like terms

7v +1

5 0
4 years ago
PLEASE HELP URGENT!!!!
Setler [38]

Answer:

A hope this helps

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Let a, b, c, and d be real numbers with a, c 6= 0. Prove that the lines y = ax+b and y = cx + d have the same x-intercept if and
Monica [59]

Step-by-step explanation:

We have got the lines :

y=ax+b\\y=cx+d

Both lines intercept the x-axis in the point :

I = (i_{1} ,i_{2})

In all point from x-axis the y-component is equal to 0.

I=(i_{1},o)

We replace the I point in the lines equations:

0=a(i_{1})+b \\0=c(i_{1})+d

From the first equation :

0=a(i_{1})+b \\-b=a(i_{1})\\i_{1}=\frac{-b}{a}

From the second equation :

0=c(i_{1})+d\\ -d=c(i_{1})\\i_{1}=\frac{-d}{c}

Then i_{1}=i_{1}

Finally :

\frac{-b}{a}=\frac{-d}{c} \\\frac{b}{a}=\frac{d}{c} \\ad=bc

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc

8 0
3 years ago
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