Question

Find the equation of a line that passes through the point (-5,4) and is perpendicular to 6x-36y

Answer 1

Answer:

$y = - 6x - 2$

Explanation

The given line is

$6x - 36y = k$

where k is the missing constant from the given equation( this has no effect on the solution in anyway)

We solve for y to get;

$y = \frac{1}{6}x - \frac{k}{36}$

The slope of this line after comparing to

y=mx+c is

$m = \frac{1}{6}$

The negative reciprocal is m=-6

The equation of the required line that passes through (-5,4) is given by

$y - 4 = - 6(x - - 5)$

We multiply through by 6 to get:

$y - 4 = - 6x - 30$

We expand to get;

$y = - 6x - 26$