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blsea [12.9K]
3 years ago
15

Find the equation of a line that passes through the point (-5,4) and is perpendicular to 6x-36y

Mathematics
1 answer:
____ [38]3 years ago
6 0

<u>Answer:</u>

y =  - 6x  - 2

<u>Explanation</u>

The given line is

6x - 36y = k

where k is the missing constant from the given equation( this has no effect on the solution in anyway)

We solve for y to get;

y =  \frac{1}{6}x - \frac{k}{36}

The slope of this line after comparing to

y=mx+c is

m =  \frac{1}{6}

The negative reciprocal is m=-6

The equation of the required line that passes through (-5,4) is given by

y  - 4 = - 6(x -  - 5)

We multiply through by 6 to get:

y - 4 =  - 6x - 30

We expand to get;

y =  - 6x - 26

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