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2 years ago

Find the HCF of 20,55,90 Pls help it is urgent if i dont get this answer i will fail

Mathematics

1 answer:

Ann [662]2 years ago

5 0

Answer:

Step-by-step explanation:

Factors of 20 = 1 2 4 5 10 20

Factors of 55 = 1 5 11 55

Factors of 90 = 1 2 3 5 6 9 10 15 18 30 45 90

Hcf = 5

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Snezhnost [94]

Ok
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3 years ago

Help on the second graph?

patriot [66]

Answer:

The 2nd Graph is a function.

Step-by-step explanation:

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3 years ago

What is the best answer to solution of x^2 + 16 = 0?

kolezko [41]

Answer:

4. C. x = 4 or -4

Step-by-step explanation:

since both terms are perfect squares, factor using the difference of squares formula, a² - b² = ( a + b ) ( $\alpha$ - b ) where

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3 years ago

Find the equation of a line with a slope 3 that includes the point (0,5)

Genrish500 [490]

Answer:

Step-by-step explanation:

We want to find the equation of a line with a slope of 3 that includes the point (0, 5).

We can use the slope-intercept form, given by:

$y=mx+b$

Where m is the slope and b is the y-intercept.

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3 years ago

Read 2 more answers

It is believed that a stock price for a particular company will grow at a rate of $5 per week with a standard deviation of $1. A

IgorLugansk [536]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = $5

For the alternative hypothesis,

µ < $5

number of samples taken = 10

Sample mean, x = (4 + 3 + 2 + 3 + 1 + 7 + 2 + 1 + 1 + 2)/10 = 2.6

To determine sample standard deviation, s

s = √(summation(x - mean)/n

n = 12

Summation(x - mean) = (4 - 2.6)^2 + (3 - 2.6)^2 + (2 - 2.6)^2 + (3 - 2.6)^2 + (1 - 2.6)^2 + (7 - 2.6)^2 + (2 - 2.6)^2 + (1 - 2.6)^2 + (1 - 2.6)^2 + (2 - 2.6)^2 = 30.4

s = √30.4/10 = 1.74

Since the number of samples is 10 and no population standard deviation is given, the distribution is a student's t.

Since n = 10,

Degrees of freedom, df = n - 1 = 10 - 1 = 9

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.6

µ = population mean = 5

s = samples standard deviation = 1.74

t = (2.6 - 5)/(1.74/√10) = - 4.36

We would determine the p value at alpha = 0.05. using the t test calculator. It becomes

p = 0.000912

7 0

3 years ago