Find the HCF of 20,55,90 Pls help it is urgent if i dont get this answer i will fail

Mathematics

1 answer:

Ann [662]3 years ago

5 0

Answer:

Step-by-step explanation:

Factors of 20 = 1 2 4 5 10 20

Factors of 55 = 1 5 11 55

Factors of 90 = 1 2 3 5 6 9 10 15 18 30 45 90

Hcf = 5

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Any help? Much appreciated

natulia [17]

Answer:

$\frac{6+\sqrt{27} }{4-\sqrt{3} } = \frac{r+s\sqrt{3} }{13} \\We\ may\ multiply\ the\ numerator\ and\ denominator\ with\ (4+\sqrt{3} ).\\Hence,\\\frac{(6+\sqrt{27})(4+\sqrt{3}) }{13} = \frac{r+s\sqrt{3} }{13} \\Hence,\\24+6\sqrt{3} +4\sqrt{27} +9= r+s\sqrt{3}\\24+6\sqrt{3} +4*3\sqrt{3} } +9= r+s\sqrt{3}\\24+6\sqrt{3} +12\sqrt{3}+9 = r+s\sqrt{3}\\33+18\sqrt{3} = r+s\sqrt{3}\\Hence,\\r=33, s=18$

5 0

3 years ago

Factorise <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="lat

Amanda [17]

Answer:

a1= 1 q= −sinx , dla |q| <1 , ta suma jest zbieżna

a1 1

1 −q 1+sinx

w mianowniku podobnie: a1=1 , q= sinx , dla | sinx| <1

1 −sinx

i mamy równanie:

1+sinx

= tg2x

1− sinx

Step-by-step explanation:

5 0

2 years ago

Based on a study of population projections for 2000 to 2050, the projected population of a group of people (in millions) can b

Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

$A(t) = 11.19(1.009)^t$

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, $t=0$ and in 2014, $t=14$ . Mathematically,

$\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}$

$A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107$

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm $y=a^x$ (where $a$ is a constant) is $\dfrac{dy}{dx}=a^x\ln a$ . Let's use in this in finding the derivative of $A(t)$ .