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klio [65]
3 years ago
7

???? Help me please

Mathematics
1 answer:
liberstina [14]3 years ago
4 0

1) I have no idea... -.-

2) $80

3) 12

4) 13

5) 42


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change the 6 ito - 6 by turning to left side then you will have -3 -6 now you can add them (- + -) is + so you can add them the sign of 6 is greater so the answer is -9

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Find the equation of locus of a point which moves such that its distance from (0,2) is one third distance from (-2,3). ( I WILL
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Answer:

8(x^2+y^2)-4x-30y+23=0

Step-by-step explanation:

<u />

<u>Distance formula</u>

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let P(x, y) = any point on the locus

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PA=\dfrac{1}{3}PB

Therefore, using the distance formula:

\implies \sqrt{(x-0)^2+(y-2)^2}=\dfrac{1}{3}\sqrt{(x-(-2))^2+(y-3)^2}

Square both sides:

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Multiply both sides by 9:

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\implies 8x^2+8y^2-4x-30y+23=0

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Step-by-step explanation:

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