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3 years ago

???? Help me please

Mathematics

1 answer:

liberstina [14]3 years ago

4 0

1) I have no idea... -.-

2) $80

3) 12

4) 13

5) 42

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3 years ago

8x – 65 = - x2<br> [pease help me

Leya [2.2K]

Answer: x=5 or x=−13

Step-by-step explanation:

8x−65=−x2

8x−65−(−x2)=−x2−(−x2)

x2+8x−65=0

(x−5)(x+13)=0

x−5=0 or x+13=0

x=5 or x=−13

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3 years ago

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3 years ago

Which equations for the measures of the unknown

MAXImum [283]

Answer: Option B, Option C, Option E

Step-by-step explanation:

The options written correctly, are:

$A)x = cos^{-1}(\frac{a}{c})\\\\B) x = sin^{-1}(\frac{c}{b})\\\\C)x = tan^{-1}(\frac{c}{a})\\\\D) y = sin^{-1}(\frac{a}{c})\\\\ E)y = cos^{-1}(\frac{c}{b})$

For this exercise you need to use the following Inverse Trigonometric Functions:

$1)\ sin^{-1}(x)\\\\2)\ cos^{-1}(x)\\\\3)\ tan^{-1}(x)\\\\$

When you have a Right triangle (a triangle that has an angle that measures 90 degrees) and you know that lenght of two sides, you can use the Inverse Trigonometric Functions to find the measure of an angle $\alpha$ :

$1)\alpha = sin^{-1}(\frac{opposite}{hypotenuse}) \\\\2)\ \alpha =cos^{-1}(\frac{adjacent}{hypotenuse})\\\\3)\ \alpha=tan^{-1}(\frac{opposite}{adjacent})$

Therefore, the conclusion is that the angles "x" and "y" can be found with these equations:

$x=sin^{-1}(\frac{c}{b})\\\\x= cos^{-1}(\frac{a}{b})\\\\x=tan^{-1}(\frac{c}{a})\\\\\\ y=sin^{-1}(\frac{a}{b})\\\\y=cos^{-1}(\frac{c}{b})\\\\y=tan^{-1}(\frac{a}{c})$

5 0

3 years ago

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