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3 years ago

Write the following percents as both fractions and decimals.

Mathematics

2 answers:

Leona [35]3 years ago

5 0

(last part)
25%
27.8%
290%
300%
67%

ValentinkaMS [17]3 years ago

5 0

Answer: fractions and decimals

1. 25% = 25/100 and 0.25

2. 32.5% = 325/1000 and 0.325

3. 4% = 4/100 and 0.04

4. 75%= 75/100 and 0.75

5. .5% = 65/1000 and 0.065

6. 125% = 125/100 and 1.25

7. 125.5% = 1255/1000 and 1.255

8. 0.2% = 2/1000 and 0.002

9. 0.75%= 75/10000 and 0.0075

10. 107% = 107/100 and 1.07

11. 210%= 210/100 and 2.1

12. 22.5%= 225/1000 and 0.225

Step-by-step explanation:

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3 years ago

What are the possible rational roots of the polynomial equation? 0=2x7+3x5−9x2+6

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Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

$a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0$

Where:

- The coefficients are integers.

- $a_n$ is the leading coeffcient ( $a_n\neq 0$ )

- $a_0$ is the constant term $a_0\neq 0$

Every rational root of the polynomial is in the form:

$\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}$

For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

Then, by Rational Roots Test we get the possible rational roots of this polynomial:

$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

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