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tia_tia [17]
3 years ago
7

What mobile operating system below requires all applications to be reviewed and approved before they can be made available in th

e App store?
Computers and Technology
1 answer:
FinnZ [79.3K]3 years ago
4 0

Answer:

The correct answer to the following answer will be iOS.

Explanation:

The iOS formerly stands for iPhone Operating System, basically is a mobile operating system developed by Apple Inc. This edition mainly supports Apple devices such as iPhone, iPod touch, iPad, etc.

Just because of this iOS gives the improvement to the entire application and is one of the operating systems which requires all that applications to be approved before showing availability in the App stores.

So, iOS is the right answer.

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Im Gonna Give Brainly a Second Chance<br><br> Everybody deserves a second chance
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Answer:

ok I know it's not for me but for who?

Explanation:

Just asking. And yes everyone deserves a second chance. Even liars?

please don't take my question wrongly have an above average day!

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The birthday paradox says that the probability that two people in a room will have the same birthday is more than half, provided
poizon [28]

Answer:

The Java code is given below with appropriate comments for explanation

Explanation:

// java code to contradict birth day paradox

import java.util.Random;

public class BirthDayParadox

{

public static void main(String[] args)

{

   Random randNum = new Random();

   int people = 5;

   int[] birth_Day = new int[365+1];

   // setting up birthsdays

   for (int i = 0; i < birth_Day.length; i++)

       birth_Day[i] = i + 1;

 

   int iteration;

   // varying number n

   while (people <= 100)

   {

       System.out.println("Number of people: " + people);

       // creating new birth day array

       int[] newbirth_Day = new int[people];

       int count = 0;

       iteration = 100000;

       while(iteration != 0)

       {

           count = 0;

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               // generating random birth day

               int day = randNum.nextInt(365);

               newbirth_Day[i] = birth_Day[day];

           }

           // check for same birthdays

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               int bday = newbirth_Day[i];

               for (int j = i+1; j < newbirth_Day.length; j++)

               {

                   if (bday == newbirth_Day[j])

                   {

                       count++;

                       break;

                   }

               }

           }

           iteration = iteration - 1;

       }

       System.out.println("Probability: " + count + "/" + 100000);

       System.out.println();

       people += 5;

   }

}

}

4 0
3 years ago
Defining a hexadecimal number as in Problem 67, write the function int hexToDec( const int hexNum[]) to convert a four-digit hex
lyudmila [28]

Answer:

#include <stdio.h>

int hexToDec(const int hexNum[]){

   int result = 0, prod = 1;

   for(int i = 3;i>=0;i-=1){

       result += (prod*hexNum[i]);

       prod = prod * 16;

   }

   return result;

}

int main()

{

   int hexNum[4], i;

   char s[5], ch;

   printf("Enter hexa decimal value: ");

   scanf("%s",s);

   

   for(i = 0;i<4;i++){

       ch = s[i];

       if(ch>='0' && ch<='9'){

         hexNum[i] = ch-'0';

      }

      else if((ch>='a' && ch<='f') || (ch>='A' && ch<='F')){

         if(ch=='A' || ch=='a'){

            hexNum[i] = 10;

         }

         else if(ch=='B' || ch=='b'){

            hexNum[i] = 11;

         }

         else if(ch=='C' || ch=='c'){

            hexNum[i] = 12;

         }

         else if(ch=='D' || ch=='d'){

            hexNum[i] = 13;

         }

         else if(ch=='E' || ch=='e'){

            hexNum[i] = 14;

         }

         else{

            hexNum[i] = 15;

         }

      }

   }

   

   printf("%d",hexToDec(hexNum));

   return 0;

}

Explanation:

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