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Evgesh-ka [11]
3 years ago
13

what is the molarity of a solution prepared by dissolving 15.0g of sodium hydroxide in enough water to make a total of 225 ml of

solution​
Computers and Technology
1 answer:
Reptile [31]3 years ago
5 0

Answer:

1.6666 g/mol = 1 \frac{2}{3} g/mol

Explanation:

Molar mass of NaOH= 23+16+1 =40g/mol

Mols in 15g = 15/40 mol

If this was dissolved in 225ml of water molarity of the solution is

\frac{15}{40} ÷ 225 x 1000 = 1.6666 g/mol = 1 \frac{2}{3} g/mol

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