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Sauron [17]
3 years ago
10

Which expression can be written as k square root 3 where k is an integer

Mathematics
1 answer:
Damm [24]3 years ago
8 0

Answer:

A simple expression is \sqrt{48} = 4\sqrt{3}

Step-by-step explanation:

Surds are irrational numbers expressed with respect to a square root. There are some basic rules required when dealing with surd.

Integers are numbers that do not have a decimal or fractional part i.e whole numbers. So, a simple expression that can be written as k square root 3 where k is an integer is \sqrt{48}.

So that,

                            \sqrt{48} = \sqrt{16 * 3}

                                   = 4\sqrt{3}

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Free piont (so this will not get delete) 7x8x3=
SVEN [57.7K]

Answer:

168

Step-by-step explanation:

5 0
2 years ago
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The slope of the line below is 1 .write the point slope equation for the line using the coordinates of the labeled point. (5,7)​
wariber [46]

Answer:

<em>y - 7 = 1 (x-5)</em>

Step-by-step explanation:

The point slope equation of a line is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is the point on the line

Given the following

m = 1

(x0, y0) = (5, 7)

Substitute into the formula

y - 7 = 1 (x - 5)

y - 7 = x -5

y = x - 5 + 7

y = x + 2

<em>Hence the point slope equation of the line is y - 7 = 1 (x-5)</em>

<em></em>

<em></em>

3 0
2 years ago
If xy + y² = 6, then the value of dy/dx at x= -1 is<br>​
mylen [45]

Hi there!

\large\boxed{\text{At (-1, -2), }\frac{dy}{dx} = -\frac{2}{5}}}

\large\boxed{\text{At (-1, 3), }\frac{dy}{dx} = -\frac{3}{5}}}

We can calculate dy/dx using implicit differentiation:

xy + y² = 6

Differentiate both sides. Remember to use the Product Rule for the "xy" term:

(1)y + x(dy/dx)  + 2y(dy/dx) = 0

Move y to the opposite side:

x(dy/dx) + 2y(dy/dx) = -y

Factor out dy/dx:

dy/dx(x + 2y) = -y

Divide both sides by x + 2y:

dy/dx = -y/x + 2y

We need both x and y to find dy/dx, so plug in the given value of x into the original equation:

-1(y) + y² = 6

-y + y² = 6

y² - y - 6 = 0

(y - 3)(y + 2) = 0

Thus, y = -2 and 3.

We can calculate dy/dx at each point:

At y = -2: dy/dx = -(-2) / -1+ 2(-2) = -2/5.

At y = 3: dy/dx = -(3) / -1 + 2(3) = -3/5.

5 0
3 years ago
Triangle TRE has vertices T(3,6), R(-3,10), and E(-9,4). Find the coordinates of point M if line TM is a median of triangle TRE
Sergeeva-Olga [200]

Answer:

The coordinate of point M = (-6,7)

Explanation:

The Median of a triangle is a line segment from a vertex to the midpoint of the opposite side of a triangle.

Given: \triangle TRE has vertices T(3,6) , R(-3,10) and E(-9,4).

Here, line TM is a median of triangle TRE where M is the midpoint of RE.

The midpoint of  M of the line segment from R(-3,10)  to E(-9,4) is;

M = (\frac{-3+(-9)}{2}, \frac{10+4}{2}) = ( \frac{-12}{2}, \frac{14}{2} )=(-6,7)

Therefore, the coordinate of point M is, (-6,7).

7 0
3 years ago
2. Find the solution set of the inequality:
m_a_m_a [10]

Answer:

The answer is B

Step-by-step explanation:

I got a giid grade

8 0
3 years ago
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