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3 years ago

The midpoint of AB is M(-2,-4). If the coordinates of A are (-3,-5), what are the coordinates of B?

Mathematics

1 answer:

Luba_88 [7]3 years ago

3 0

Answer:

B(-1,-3)

Step-by-step explanation:

let the coordinates of B be (x,y)

Mid point of AB = (x₁+ x₂/2, y₁+y₂ /2)

= (-3 +x/2 , -5+y/2)

Mid point of AB is M(-2,-4)

(-3 +x/2 , -5+y/2) = (-2, -4)

-3 + x /2 = -2 ; -5+y/2 = -4

-3 + x = -2 * 2 ; -5 + y = -4 * 2

-3 + x = -4 ; -5 + y = -8

x = -4 +3 ; y = -8 +5

x = -1 ; y = -3

B(-1,-3)

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Bezzdna [24]

Answer:

Step-by-step explanation:

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3 years ago

How could you graph an inequality like this x>3?

Firlakuza [10]

Answer:

see below

Step-by-step explanation:

The graph of it on a number line is an open circle at x=3 with a line extending to the right through larger numbers.

When the inequality does not include the "or equal to" case, the boundary is graphed as a dashed line (on an x-y plane) or open circle (on a number line). The shaded area covers values of the variable that meet the condition of the inequality. Here, those are values of x that are more than 3.