Help me .......... . Math ..... Note l want answer true.......please

Evaluate 14 y / 2 for y equals 6

ad-work [718]

Answer:

42

Step-by-step explanation:

Now we know that y=6, change the y to 6. Then solve, 14x6 is 84, and 84 divided by 2 is 42.

7 0

3 years ago

Your office is raising money for charity by collecting aluminium cans for recycling. They get 36p per kilo of cans. A kilo is ap

Alina [70]

8645 cans divided by 72 per kilo is 120.069 kilos of cans
120.069 kilos times 0.36 pounds= 43.22 pounds raised

8 0

2 years ago

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the length of each side of the ABCD EFGH cube is 6cm. If point P is located in the middle of line EH, point Q is in the middle o

azamat

Answer:

The distance is: $\sqrt3\ cm\approx1,73\,cm$

Step-by-step explanation:

The distance of point E to the PQR plane it is the hight (vertical) of piramid PRQE

If point P is located in the middle of line EH, point Q is in the middle of line EF, and point R is in the middle of line AE than:

EP = EQ = ER = 0.5EF = 3 cm and m∠REQ = m∠QEP = m∠REP = 90° so triangles RQE, QPE and PRE are congruent.

RQ = QP = PR so triangle PQR is equilateral and from Pythagorean theorem (for ΔRQE):

$RQ^2=ER^2+EQ^2=3^2+3^2=2\cdot3^2\ \ \implies\ \ RQ=3\sqrt2$

Then: $RN=\dfrac{RQ\,\sqrt3}2$

and: $RK=\dfrac23RN=\dfrac{RQ\,\sqrt3}3=\dfrac{3\sqrt2\cdot\,\sqrt3}3=\sqrt6$

Therefore from Pythagorean theorem (for ΔERK):

$EK^2+RK^2=ER^2\\\\EK^2=ER^2-RK^2\\\\EK^2=3^2-(\sqrt6)^2\\\\EK^2=9-6=3\\\\EK=\sqrt3\ cm\approx1,73\,cm$

8 0

3 years ago

Consider the probability that at least 88 out of 158 software users will not call technical support. Assume the probability that

Nookie1986 [14]

Answer:

$E(X) = 158*0.57 =90.06$

And the standard deviation for the random variable is given by:

$\sigma= \sqrt{158*0.57*(1-0.57)} = 6.223$

And the distribution for the approximation is given by:

$X \sim N (\mu = 90.06, \sigma = 6.223)$

We can use the z score formula given by:

$z = \frac{x -\mu}{\sigma}$

And using the complement rule we got:

$P(X \geq 88) = 1-P(X$

And using the standard normal table we got:

$P(X \geq 88) = 1-P(X$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n = 158, p =0.57)$