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Vanyuwa [196]
3 years ago
8

7) A number less than 0 is called _ _ _ _ _ _ _ _ _ _ _ _ _ _.

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0

Answer:

A negative

Step-by-step explanation:

Any number below 0 is called a negative

Kipish [7]3 years ago
7 0

Answer:

A negative number

When looking at a number line, there is a zero, but on the left, there's more numbers.

<   -2      -1      0       1      2    >    

I hope this helps.

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Mr. Sweeney's car can travel 195 miles on 10 gallons of gas. How far
VikaD [51]

Answer:

Miles in 10 gallons = 195

Miles in 1 gallon = 195/10 = <u>1</u><u>9</u><u>.</u><u>5</u>

Miles in 18 gallons = 19.5 × 18 = <u>3</u><u>5</u><u>1</u><u> </u><u>miles</u><u>.</u>

6 0
3 years ago
Read 2 more answers
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
Which ratios are equivalent to 10:16? Check all that apply. 30 to 48 25:35 StartFraction 40 Over 64 EndFraction 8:32 5 to 15
schepotkina [342]

Answer:

30 to 48, 40/64

Step-by-step explanation:

Which ratios are equivalent to 10:16, and they gave us 30 to 48, 25:35, 40/64, 8/32 and 5 to 15.

For 30 to 48, we can mulitply the 10:16 by 3 to give us 30:48, so it is <u>equal</u>.

For 25:35, we simplify it to 5:7, while 10:16 is 5:8, so they are <u>not equal</u>.

For 40/64, we can take 10:16 and multiply them by 4, getting the same number. Therefore, it is <u>equal</u>.

For 8/32, we can simplify it down to 1/4, while 10:16 simplifies down to 5:8, it is  <u>not equal</u>.

Lastly, for 5 to 15, w can simplify that to 1/3, and get 5:8 for 10:16, so it <u>won't be equal.</u>

4 0
3 years ago
Read 2 more answers
Select all the expressions that are equivalent to 4b:
Alinara [238K]

Answer:

No. 1 , 3 and 5 is correct.

8 0
3 years ago
A square has an area of 64 square centimeters. What is the length of one side of the square?
larisa86 [58]

Answer:

It is 16 because a square has 4 sides. 64 divided by 4 sides is 16 square centimeters per one side. Hope this helps

6 0
3 years ago
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