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adoni [48]
3 years ago
5

1 point

Mathematics
1 answer:
-Dominant- [34]3 years ago
5 0
39
Divide 78 by 2 to get 39 and add in to the number
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Given: AABC, m_ACB=90°,<br> CD 1 AB, m ZACD=60º,<br> BC = 6 cm<br> Find: CD, Area of AABC
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Answer:

Look below

Step-by-step explanation:

Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.

This means triangle BCD is a 30-60-90 (angle measures) right triangle

The proportions of the sides (from smallest to largest) is

x:x√3:2x

We are given that BC = 6 cm. This means...

2x=6

x=3

This means DB is 3 cm and CD is 3√3 cm

Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.

x=3√3

x√3=9

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Now we need to find AB

AB = AD + DB

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AB = 12 cm

Area = \frac{1}{2} bh = \frac{1}{2}(12)(3\sqrt3)=6(3\sqrt3)=18\sqrt3

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