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3 years ago

Perimeter of a mirror is 260. The length is x cm. Find the height of the mirror in terms of x

1 answer:

4 0

$\bf \textit{perimeter of a rectangle}\\\\ P=2(L+h)~~ \begin{cases} L=length\\ h=height\\[-0.5em] \hrulefill\\ P=260\\ L=x \end{cases}\implies 260=2(x+h) \\\\\\ \cfrac{260}{2}=x+h\implies 130=x+h\implies 130-x=h$

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Give the slope-intercept form for the equation.<br><br> 5x+ 2y = -14

irga5000 [103]

Answer:

$y=-\frac{5}{2} x-7$

Step-by-step explanation:

$5x+2y=-14\\\frac{5x}{2} +\frac{2y}{2} =\frac{-14}{2}$

$\frac{5}{2}x+y=-7$

$y=-\frac{5}{2} x-7$

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3 years ago

Graph this equation y=3sin(2x-5)

OLEGan [10]

Y = 3sin(2x - 5)
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3 years ago

11. Explain how to evaluate the expression 9 +(45 x 2) = 10.

Dmitry_Shevchenko [17]

The Answer Is 18

Order Of Operation laws says that you must do the parentheses first, 45x2.

45x2=90

The next thing you must do is divide 90 by 10 since division is before addition.

90/10=9

Now combine like terms.

9+9=18

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3 years ago

Read 2 more answers

Joe is going for a walk. He walks at a speed of 3 miles per hour for 7.5 miles. For how many hours does he walk?

Ksju [112]

Answer: 2.5 hours
explanation:
7.5/3=2.5

6 0

3 years ago

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

3 years ago